Answer: if you are going to put it like p^2-m^2 no one going to have that answer so I need the p and the m like for example the p=5 and the m=4
Step-by-step explanation: so it going to be like
Evaluate for m=4,p=5
5^2−4^2
=9
So I can’t answer how you put it
Answer:
40
Step-by-step explanation:
Answer:
-2 > x < 2
Step-by-step explanation:
Given that:
2x + 6 > 2
Subtracting 6 from both sides:
2x + 6 -6 > 2-6
2x > -4
Dividing by 2 on both sides:
x > -2
For second equation:
5x< 6 + 2x
Subtracting 2x from both sides:
5x - 2x < 6 + 2x -2x
3x < 6
Dividing by 3 on both sides:
x < 2
Result: -2 > x < 2
Answer: Dimensions of A are of length [L]
Dimensions of B are of 
Dimensions of C are of 
Step-by-step explanation:
The given equation is
Since the dimension on the L.H.S of the equation is [L] , each of the terms on the right hand side should also have dimension of length[L] to be dimensionally valid
Thus
Dimensions of A = [L]
Dimensions of Bt = [L]
![Bt=[L]\\\\](https://tex.z-dn.net/?f=Bt%3D%5BL%5D%5C%5C%5C%5C)
![[B][T]=[L]](https://tex.z-dn.net/?f=%5BB%5D%5BT%5D%3D%5BL%5D)
![\\\\\therefore [B]=LT^{-1}](https://tex.z-dn.net/?f=%5C%5C%5C%5C%5Ctherefore%20%5BB%5D%3DLT%5E%7B-1%7D)
Similarly
Dimensions of ![Ct^{}2 = [L]](https://tex.z-dn.net/?f=Ct%5E%7B%7D2%20%3D%20%5BL%5D)
![Ct^{2}=[L]\\\\[C][T]^{2}=[L]\\\\\therefore [C]=LT^{-2}](https://tex.z-dn.net/?f=Ct%5E%7B2%7D%3D%5BL%5D%5C%5C%5C%5C%5BC%5D%5BT%5D%5E%7B2%7D%3D%5BL%5D%5C%5C%5C%5C%5Ctherefore%20%5BC%5D%3DLT%5E%7B-2%7D)
Answer:
It's b
it's kinda hard to explain but it ends up showing .7x.5 on the example, so your answer is B
