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Kitty [74]
2 years ago
8

Solve pls brainliest! the first one to answer it gets the brainliest

Mathematics
1 answer:
mart [117]2 years ago
5 0

Answer:

2.4

Step-by-step explanation:

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WILL MARK BRAINLIEST TO THE BEST ANSWER!!
ruslelena [56]

\dfrac{12^3}{12^7} = 12^{3 - 7} = 12^{-4} = \dfrac{1}{12^4}

Answer: B

8 0
3 years ago
Read 2 more answers
Find a set of four integers such that their order and the order of their absolute values are the same.
Vinvika [58]

If you pick only positive numbers, the absolute value will have no effect, and the original set and the set of the absolute value will be exactly the same:

A = \{1,2,3,4,5\}

is still

A = \{|1|,|2|,|3|,|4|,|5|\} = \{1,2,3,4,5\}

8 0
2 years ago
diep buys a load of bread 65 centimeters long. for lunch every afternoon, he cuts 15 centimeters of bread for his sandwich. diep
LiRa [457]

Answer:

Continuous

Step-by-step explanation:

Its continous because after each day you take the same  amount away and due to that it will be continous.

6 0
3 years ago
A, B and C are events such that P(A) = 1/3, P(B) = ¼, and P(C) = 1/5. Find P(AUBUC) under each of the following assumptions: a)
marta [7]

(a) If A,B,C are mutually exclusive, then

P(A\cap B)=P(A\cap C)=P(B\cap C)=P(A\cap B\cap C)=0

so we have

P(A\cup B\cup C)=P(A)+P(B)+P(C)=\dfrac{47}{60}

(b) If A,B,C are mutually independent, then

P(A\cap B)=P(A)P(B),

P(A\cap C)=P(A)P(C),

P(B\cap C)=P(B)P(C),

P(A\cap B\cap C)=P(A)P(B)P(C)

so that

P(A\cup B\cup C)=P(A)+P(B)+P(C)-(P(A\cap B)+P(A\cap B)+P(B\cap C))+P(A\cap B\cap C)

P(A\cup B\cup C)=\dfrac{47}{60}-\left(\dfrac1{12}+\dfrac1{15}+\dfrac1{20}\right)+\dfrac1{60}

P(A\cup B\cup C)=\dfrac35

5 0
3 years ago
Hi I just have a question how do you divide 18/32 with out a calculator.
Bingel [31]
First set it up like this:32 \sqrt{18}
<span>then add a zero on to the 18 and a decimal point like this: </span>32 \sqrt{18.0}
then solve for 180/32 and add a decimal in the same location that it is in the 18.0 Hope this helps!
8 0
3 years ago
Read 2 more answers
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