Solution :
int f(int x){
;
}*/
int f(
){
int stack[2] = {
};
;
;
;
R1 = R1 * C; /*R1 =
*/
;
* R2; /* R0 = bx */
; /*R0 =
*/
;
; /*R0 = a+bx+cx^2 */
}
/*
int s=0;
{
;)
*/
AREA SumSquares, code, readWrite
ENTRY
;loop
MOV r1, #0 ; s = 0
Loop
;calculate i*i
;s = s+ i*i
, #1 ; i = i+1
,#10 ; test for end
Loop ;
END
Answer:
1
11
111
1111
11111
Explanation:
Given
The above QBasic code
Required
The output
The iteration on the third line is repeated 5 times; i.e. for values of j from 1 to 5.
In each iteration, the value of N is printed and the next value is calculated.
Initially, the value of N is 1 ---- on line 2
So, 1 is printed first. The next value of N is as follows:
--- we keep replacing N (on the right-hand side) with current N value.
So, we have:




The answer is: switches.
Explanation:
Filtering is a function of switches.
Answer:
patent
Explanation:
A patent is an intellectual property, with this legal protection, we can exclude to use, sell, and importation of an invention for a limited period of years, but we must do an enabling public disclosure of the invention or discovery, it is a requirement of the patent law, a patent is considered an advantage in the industries world.