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3 years ago

Two sides of a triangle are 11 can and 14 cm what are all the possible values for the length of the third side

Mathematics

1 answer:

AlexFokin [52]3 years ago

8 0

Answer:

Step-by-step explanation:

The third side is thus, less than 14 + 11 = 25 cm. The side cannot be less than the difference of the two sides. Thus, the third side has to be more than 14 - 11 = 3 cm. So, the length of the third side could be any length greater than 3 cm and less than 25 cm.

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Match the steps to find the equation of the parabola with focus (-1, 2) and directrix x = 5.

Archy [21]

Answer:

The matched options to the given problem is below:

Step1: Choose a point on the parabola

Step2: Find the distance from the focus to the point on the parabola.

Step3: Use (x, y).

Find the distance from the point on the parabola to the directrix.

Step4: Set the distance from focus to the point equal to the distance from directrix to the point.

Step5: Square both sides and simplify.

Step6: Write the equation of the parabola.

Step by step Explanation:

Given that the focus (-1,2) and directrix x=5

To find the equation of the parabola:

By using focus directrix property of parabola

Let S be a point and d be line

focus (-1,2) and directrix x=5 respectively

If P is any point on the parabola then p is equidistants from S and d

Focus S=(-1,2), d:x-5=0

Step1: Let P(x,y) be any point on parabola

Step2: Therefore the $d=\sqrt{(x+1)^2+(y-2)^2}\hfill (1)$

Step3: The perpendicular distance from p to d is

$\frac{|x-5|}{\sqrt{(-1)^2+2^2}}$

$=\frac{|x-5|}{\sqrt{5}}\hfill (2)$

Step4: equating (1) and (2)

$\sqrt{(x+1)^2+(y-2)^2}=\frac{|x-5|}{\sqrt{5}}$

Step5: squaring on both sides

$(x+1)^2+(y-2)^2=\frac{|x-5|^2}{5}$

$5[(x+1)^2+(y-2)^2]=(x-5)^2$

$5[x^2+2x+1+y^2-2y+4-x^2+10x-25]=0$

$12x+y^2-2y-24=0$

Step6: Equation of the parabola is

$y^2-2y+12x-24=0$

8 0

3 years ago

Express your answer in lowest terms 6/20 + 14/20

Molodets [167]

Answer:1

Step-by-step explanation:

6/20+14/20=

20/20

7 0

3 years ago

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A team of runners is needed ti run 1/4- mile relay race.if each runner must run 1/16 mile,how many runners will be needed

Pavel [41]

If each runner must run 1/16 of 1/4 mile then you need 4 runners because four runners makes 4/16 points. this number is equivalent to 1/4 which proves this statement true

4 0

3 years ago

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What is a common multiple for 8,12,10

vagabundo [1.1K]

2 is a common multiple for 8,12,10

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3 years ago

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D -e/3d + e= e, for d

navik [9.2K]

Answer:

$\large\boxed{d=\dfrac{e^2+e}{1-3e}}$

Step-by-step explanation:

$\dfrac{d-e}{3d+e}=e\\\\\dfrac{d-e}{3d+e}=\dfrac{e}{1}\qquad\text{cross multiply}\\\\(1)(d-e)=(e)(3d+e)\qquad\text{use the distributive property}\\\\d-e=3de+e^2\qquad\text{add}\ e\ \text{to both sides}\\\\d=3de+e+e^2\qquad\text{subtract}\ 3de\ \text{from both sides}\\\\d-3de=e^2+e\qquad\text{distribute}\\\\d(1-3e)=e^2+e\qquad\text{divide both sides by}\ (1-3e)\\\\d=\dfrac{e^2+e}{1-3e}$

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3 years ago