The mass of hydrogen in 57.010 g ammonium hydrogen phosphate, (NH₄)H₂PO₄ is 2.97 g
<h3>Determination of mass of 1 mole of (NH₄)H₂PO₄ </h3>
1 mole of (NH₄)H₂PO₄ = 14 + (4×1) + (2×1) + 31 + (16×4) = 115 g
<h3>Determination of the mass of H in 1 mole of (NH₄)H₂PO₄ </h3>
Mass of H = 6H = 6 × 1 = 6 g
<h3>Determination of the mass of H in 57.010 g of (NH₄)H₂PO₄ </h3>
115 g of (NH₄)H₂PO₄ contains 6 g of H.
Therefore,
57.010 g of (NH₄)H₂PO₄ will contain = (57.010 × 6) / 115 = 2.97 g of H
Thus, 2.97 g of Hydrogen, H is present in 57.010 g of (NH₄)H₂PO₄
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Imperialism needed two things to work, they were land and trade.
In the case above, Smith does not need anything, or nothing is required to occur to establish a PMA.
<h3>What is an advancement exam?</h3>
An advancement exam is known to be one that gives an unbiased factor in regards to the Final Multiple Score (FMS) algorithm and it is said to help in the rank order of qualified candidates in terms of advancement consideration.
Hence, In the case above, Smith does not need anything, or nothing is required to occur to establish a PMA.
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po3 Smith is elligible to take the po2 advancement exam. The only evaluation he received in his current paygrade is a frocked evaluation. what, if anything, is required to occur to establish a pma.
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Nah there is nothing like that abd dont even believe
