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Alexeev081 [22]
3 years ago
9

How do i find the slope-intercept form for 6x=8y+10

Mathematics
1 answer:
Mamont248 [21]3 years ago
8 0

Answer:

y = 3/4x - 5/4

Step-by-step explanation:

6x=8y+10

Well you must first get your equation set up into the form called "Slope intercept."

6x=8y+10

Add 8y on both of your sides because your y is suppose to be alone.

8y + 6x = 10

Subtract 6x on both sides since it is in fact the opposite of addition.

8y = 6x + 10

Now, you will divide by 8 on both sides. When doing this your y will be alone.

y= 6/8x + 10/8

Note: You can leave it like this but you want to probably simplify.

y = 3/4x + 5/2

      or

y = 3/4x - 5/4

(Hope this helps can I pls have brainlist (crown)☺️)

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kotegsom [21]

Answer:

  1. x=8, x=2
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Step-by-step explanation:

For the equation ...

  y = a(x -h)² +k

you can find the x-intercepts by setting y=0 and solving for x.

  0 = a(x -h)² +k

  -k = a(x -h)² . . . . . . subtract k

  -k/a = (x -h)² . . . . . divide by a

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  h ± √(-k/a) = x . . . . add h . . . . this is the general solution

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So, for each of your problems, fill in the corresponding numbers and do the arithmetic. If (-k/a) is a negative number, the square root gives imaginary values, so there is "no solution".

1.  x = 5 ± √9 = {5 -3, 5 +3} = {2, 8} . . . . the x-intercepts are 2 and 8

2.  x = -3 ± √(-2) . . . . . . no solution; the roots are complex

3.  x = 5 ± √(-8/4) . . . . . no solution; the roots are complex

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