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zzz [600]
3 years ago
5

Steven walked 3 miles and drove 24 miles. Maureen walked 3 miles and drove

Mathematics
2 answers:
leva [86]3 years ago
8 0
Maureen has the greatest ratio
kolbaska11 [484]3 years ago
4 0

Answer:

Maureen has a greater ratio because 3/18 > 3/24

Step-by-step explanation:

Please give me brainliest :)

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PLEASE HELP ASAP! THANKS SO MUCH
Dimas [21]

27÷36=75

75% of the hats are baseball hats

8 0
3 years ago
HLEP PMG PLSakkwkwksksk
Alex_Xolod [135]

Answer:

3 is the constant

Step-by-step explanation:

12 times 3 = 36

18 times 3 = 54

25 times 3 = 54

5 0
3 years ago
Five individuals from an animal population thought to be near extinction in a certain region have been caught, tagged, and relea
Talja [164]

Answer:

a) For this case the random variable X follows a hypergometric distribution.

b) E(X)= n\frac{M}{N}=10 \frac{5}{25}=2

Var(X)=n \frac{M}{N}\frac{N-M}{N}\frac{N-n}{N-1}=10\frac{5}{25}\frac{25-5}{25}\frac{25-10}{25-1}=1

c) P(X=0)= \frac{(5C0)(25-5 C 10-0)}{25C10}=\frac{1*184756}{3268760}=0.0565

d) P(X=5)= \frac{(5C5)(25-5 C 10-5)}{25C10}=\frac{1*15504}{3268760}=0.00474

Step-by-step explanation:

The hypergometric distribution is a discrete probability distribution that its useful when we have more than two distinguishable groups in a sample and the probability mass function is given by:

P(X=k)= \frac{(MCk)(N-M C n-k)}{NCn}

Where N is the population size, M is the number of success states in the population, n is the number of draws, k is the number of observed successes

The expected value and variance for this distribution are given by:

E(X)= n\frac{M}{N}

Var(X)=n \frac{M}{N}\frac{N-M}{N}\frac{N-n}{N-1}

a. What is the distribution of X?

For this case the random variable X follows a hypergometric distribution.

b. Compute the values for E(X) and Var(X)

For this case n=10, M=5, N=25, so then we can replace into the formulas like this:

E(X)= n\frac{M}{N}=10 \frac{5}{25}=2

Var(X)=n \frac{M}{N}\frac{N-M}{N}\frac{N-n}{N-1}=10\frac{5}{25}\frac{25-5}{25}\frac{25-10}{25-1}=1

c. What is the probability that none of the animals in the second sample are tagged?

So for this case we want this probability:

P(X=0)= \frac{(5C0)(25-5 C 10-0)}{25C10}=\frac{1*184756}{3268760}=0.0565

d. What is the probability that all of the animals in the second sample are tagged?

So for this case we want this probability:

P(X=5)= \frac{(5C5)(25-5 C 10-5)}{25C10}=\frac{1*15504}{3268760}=0.00474

4 0
3 years ago
Please help me due today?
prohojiy [21]
7x - 1 = 4x + 8
3x = 9
x = 9

ABD
7(3) - 1
21 - 1
20

DBC
4x + 8
4(3) + 8
12 + 8
20

3x - 17 + x + 40 + 2x - 5 = 180
6x + 18 = 180
6x = 198
x = 33

3(33) - 17
99 - 17
82

33 + 40
73

2(33) - 5
66 - 5
61
3 0
3 years ago
The midpoint between the points (0,4) And (-4,-12)
olasank [31]
Midpoint coordinates= ((x1+x2)/2 , (y1+y2)/2)
                                 =((0+-4)/2 , ( 4+-12)/2)
                                  = (-2, -8)
5 0
4 years ago
Read 2 more answers
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