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m_a_m_a [10]
2 years ago
9

HELP BRAINIEST IF CORRECT!!!!!

Mathematics
1 answer:
Semmy [17]2 years ago
3 0

Answer: always decreasing

Step-by-step explanation:

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You have an office building that is 600 square feet in area. What are two possible dimensions how your office could be construct
stepan [7]

Answer:

20\ ft  by  30\ ft

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Step-by-step explanation:

In this problem I'm assuming the office is rectangular.

so

The area of rectangle is equal to

A=LW

where

L is the length of the rectangle

W is the width of the rectangle

In this problem we have

A=600\ ft^{2}

so

600=LW ------> equation A

Find two possible dimensions of the office

case A) Assume  a length side L and find the value of W in the equation A

so

For L=30\ ft

substitute in the equation and solve for W

600=(30)W

W=600/30=20\ ft

The dimensions are 20\ ft  by  30\ ft

case B) Assume  a length side L and find the value of W in the equation A

so

For L=40\ ft

substitute in the equation and solve for W

600=(40)W

W=600/40=15\ ft

The dimensions are 15\ ft  by  40\ ft

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3 years ago
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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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