Question

Find the equation of the line passing through the following : (-1;6) and (-3;0)

Answer 1

Answer:

Step-by-step explanation:

$(x_{1} , y_{1}) = (-1,6)\\\\(x_{2},y_{2}) = ( -3, 0)\\\\Slope =\dfrac{y_{2}-y_{1}}{x_{2}-x_1}}\\\\\\=\dfrac{0-6}{-3+1}\\\\\\=\dfrac{-6}{-2}\\\\=3$

Equation of the line: y= mx +b

y = 3x + b

Substitute ((-1 , 6) in the above equation

6 = 3*(-1) + b

6 = -3+b

6 +3  = b

b = 9

y = 3x + 9