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Illusion [34]
2 years ago
11

Find the equation of the line passing through the following : (-1;6) and (-3;0)

Mathematics
1 answer:
Licemer1 [7]2 years ago
6 0

Answer:

Step-by-step explanation:

(x_{1} , y_{1}) = (-1,6)\\\\(x_{2},y_{2}) = ( -3, 0)\\\\Slope =\dfrac{y_{2}-y_{1}}{x_{2}-x_1}}\\\\\\=\dfrac{0-6}{-3+1}\\\\\\=\dfrac{-6}{-2}\\\\=3

Equation of the line: y= mx +b

y = 3x + b

Substitute ((-1 , 6) in the above equation

6 = 3*(-1) + b

6 = -3+b

6 +3  = b

b = 9

y = 3x + 9

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The predictive value of a positive test is 18.2%.

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\begin{array}{c}\\\left( \begin{array}{l}\\{\rm{Positive Predictive }}\\\\{\rm{value}}\left( {PPV} \right)\\\end{array} \right) = \frac{{{\rm{Prevalence}} \times {\rm{Sensitivity}}}}{{\left( {{\rm{Prevalence}} \times {\rm{Sensitivity}}} \right) + \left( {{\rm{1 - Prevalence}} \times 1 - {\rm{Specificity}}} \right)}}\\\\ = \frac{{0.1 \times 0.60}}{{\left( {0.1 \times 0.60} \right) + \left( {1 - 0.1 \times 1 - 0.70} \right)}}\\\\ = \frac{{0.06}}{{0.33}}\\\\ = 0.181818\\\\ = 0.182{\rm{ }}\left( {{\rm{Round to 3 decimal place}}} \right)\\\end{array}  

(Positive Predictive  value, PPV) =

(Prevalence×Sensitivity)/Prevalence×Sensitivity +(1−Prevalence×1−Specificity)  

=   (0.1×0.60)/0.1×0.60  + (1−0.1×1−0.70) ​  

=    0.06 /0.33    

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(Positive Predictive  value, PPV) = 0.182 (3decimals)    

We have to convert the PPV into percentage,

\begin{array}{c}\\PPV = 0.182 \times 100\\\\ = 18.2\% \\\end{array}  

PPV=0.182×100

= 18.2% ​  

Therefore, the predictive positive value is 18.2%.

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