What value of x satisfies the equation 1/2 x-5(x-1/3)=5/4 x+3
2 answers:
Answer:
x - (5 -sqrt149 ) / 4 and x- (sqrt149+5)/4 = = x - -4.3016389 and x - 4.3016389
Step-by-step explanation:
1/2 x-5(x-1/3)=5/4 x+3 = ( 1/2x^2-5x -1/6x -5/3) = (5/4x+3) = ( 1/2x^2-6 5/6) = (5/4x+3) convert 5/4 to 12ths = *3 = 15/12 and 5/6 * 2 = 10/12 = ( 1/2x^2-6 10/12) = (15/12x+3) = 1/2 x^2 - 15/12x -6 10/12 - 3 = 0 = 1/2 x^2 - 15/12x -3 10/12 = 0 then multiply by 2 to make 1/2 whole 1/2 x^2 (2)- 15/12x (2) -3 10/12 (2) = 0 = x^2 - 30 /12x -6 20/12 (2) = 0 simplify irregular fraction x^2 - 2 2/4x -7 3/4 = 0 then do the abc quadratic formula = x - (5 -sqrt149 ) / 4 and x- (sqrt149+5)/4 = x- -17.2065556/4 = x - -4.3016389 and 17.2065556/4 =x - 4.3016389
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