Answer:
Hence after 3.98 sec i.e 4 sec Object will hit the ground .
Step-by-step explanation:
Given:
Height= 6 feet
Angle =28 degrees.
V=133 ft/sec
To Find:
Time in seconds after which it will hit the ground?
Solution:
<em>This problem is related to projectile motion for objec</em>t
First calculate the Range for object and it is given by ,
(2Ф)/
Here R= range g= acceleration due to gravity =9.8 m/sec^2
1m =3.2 feet
So 9.8 m, equals to 9.8 *3.2=31.36 ft
So g=31.36 ft/sec^2. and 2Ф=2(28)=56
fts
Now using Formula for time and range as
Vx is horizontal velocity
Ф
(28)
ft/sec
So above equation becomes as ,
T is approximately equals to 4 sec.
It factorises to -
4(x+6)
Answer:
D
Step-by-step explanation:
Under a counterclockwise rotation about the origin of 90°
a point (x, y) → (- y, x)
A translation of 3 units up → + 3 in the y- direction, that is add 3 to the y- coordinate, hence
(x, y) → (- y, x) → (- y, x+ 3) → D
Answer:
confidence interval:
This tells us the degree of certainty or uncertainty that is existent in a sampling method. It gives us a range of values, telling us we are fairly sure that our true value or parameter lies within the range.
Degree of confidence:
This tells us that the confidence interval has captured the true/exact population parameter.
If we have 95% degree of confidence, we are 95% sure that that the exact/true parameter are in the confidence interval
Answer:
3.315
Step-by-step explanation:
