Bro whats is 3,972 divde 12

Solve -4x+2>26 A. x > -6 B. x > 6 C. x < 6 D. x < -6

NikAS [45]

Answer:

D

Step-by-step explanation:

-4 * -6 is -34

add 2 and you have -24

6 0

3 years ago

A town has 5000 people in year t = 0. Calculate how long it takes for the population P to double once, twice, and three times, a

UNO [17]

Answer:

Step-by-step explanation:

At the time t = 0, population of the town = 5000

Rate of population increase = 500 per year

Therefore, the equation that will represent the population will be

$P_{t}=P_{0}+500t$

Where $P_{t}$ = Population after t years

$P_{0}$ = Initial population

t = Time in years

a). For double once the population will be 500×2 = 10000

By plugging in the values in the equation,

10000 = 5000 + 500t

500t = 10000 - 5000

500t = 5000

t = $\frac{5000}{500}$

t = 10 years

For Double twice,

Population will be = 10000×2 = 20000

Now we plug in the values in the equation again

20000 = 5000 + 500t

500t = 20000 - 5000

500t = 15000

t = $\frac{15000}{500}$

t = 30 years

For double thrice,

Population of the town = 20000×2 = 40000

Now we plug in the values in the equation,

40000 = 5000 + 500t

500t = 40000 - 5000

500t = 35000

t = $\frac{35000}{500}$

t = 70 years

b). If the population growth is 5%.

Then the growth will be exponential represented by

$T_{n}=T_{0}(1+\frac{r}{100})^{t}$

$T_{n}$ = Population after t years

$T_{0}$ = Initial population

t = time in years

For double once,

Population after t years = 10000

$10000=5000(1+\frac{5}{100})^{t}$

$(1.05)^{t}=\frac{10000}{5000}$

$(1.05)^{t}=2$

Take log on both the sides

$log(1.05)^{t}=log2$

tlog(1.05) = log2

t = $\frac{log2}{log1.05}$

t = 14.20 years

For double twice,

Population after t years = 20000

$20000=5000(1+\frac{5}{100})^{t}$

$(1.05)^{t}=\frac{20000}{5000}$

$(1.05)^{t}=4$

Take log on both the sides

$log(1.05)^{t}=log4$

tlog(1.05) = log4

t = $\frac{log4}{log1.05}$

t = 28.413 years

For double thrice

Population after t years = 40000

$40000=5000(1+\frac{5}{100})^{t}$

$(1.05)^{t}=\frac{40000}{5000}$

$(1.05)^{t}=8$

Take log on both the sides

$log(1.05)^{t}=log8$

tlog(1.05) = log8

t = $\frac{log8}{log1.05}$

t = 42.620 years

4 0

2 years ago

Carmen sells electronics. She made a 10% commission on every dollar sale that she makes. One month Carmen got a commission check

777dan777 [17]

Answer:

Carmen made $25,000 in sales in the month.

Step-by-step explanation:

To find the total number of sales, start with the amount she made in commission and then divide by the percentage of commission that she makes.

$2,500/10% = $25,000

7 0

2 years ago

My friend didn’t do this and he got another question ASAP

AysviL [449]

Answer: B.) I and II

Step-by-step explanation: remember doing this in like- middle school so you're welcome! it should be the right answer(:

4 0

2 years ago

Plz Answer 10 points

Lapatulllka [165]

I'll say the first one and the second last one, because the other ones don't make sense to me...

4 0

2 years ago

Read 2 more answers