Y = (x - 3)² + 53
y = (x - 3)(x - 3) + 53
y = (x(x - 3) - 3(x - 3)) + 53
y = (x(x) - x(3) - 3(x) + 3(3)) + 53
y = x² - 3x - 3x + 9 + 53
y = x² - 6x + 62
Answer:
<em>y = 8</em>
Step-by-step explanation:
330x + 1220y = 12730 (cost of coach tickets plus cost of first class tickets is total budget)
x + y = 17 (number of coach tickets plus number of first class tickets is total number of people)
Solve the second equation for y to get y = 17 - x, then plug that into the first equation and solve for x:
330x + 1220(17 - x) = 12730
330x + 20740 - 1220x = 12730
-890x + 20740 = 12730
-890x = -8010
x = 9
Sarah bought x = 9 coach tickets. Plug that into the second equation and solve for y:
9 + y = 17
y = 8
Sarah bought y = 8 first class tickets.
Answer:
Step-by-step explanation:
We'll call the 2 numbers x and y. Starting with the last part of that first sentence "one number is 10 times the other number" can be written, in algebraic form:
y = 10x
Now on to the first statement about the numbers: "twice their sum" is 2(x + y) and "equals their product" is = xy. Putting that all together:
2(x + y) = xy and we know that y = 10x so
2(x + 10x) = x(10x) and
and
and
x(10x - 22) = 0 so
x = 0 or 10x - 22 = 0 which makes
x equal to 
So x = 2.2 and y = 22.