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frutty [35]
3 years ago
11

Voting for the government to institute a price below market equilibrium, the price ceiling, is a great way to get more gas to pe

ople for less money. True or false
Based on mr Clifford videos governresourcesment attempts to control and manipulate prices will usually result in a misallocation of resources true or false

A price floor is the maximum price you may charge for an item true or false
A PRICE floor set above market equilibrium price will generally cause a surplus or shortage . A place set below equilibrium will lead to a shortage or surplus
A price ceiling set above market equilibrium price will have no effect on the market true or false ?
Mathematics
1 answer:
PolarNik [594]3 years ago
6 0

Answer:

Step-by-step explanation:

idek

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4. You want to know if there's an association between college students' spring break destinations and what year they're in. You
Pachacha [2.7K]

Answer:

\chi^2 =27.356

p_v = P(\chi^2_{9} >27.356)=0.00122

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(27.356,9,TRUE)"

Since the p value is lower than the significance level assumed 0.05 we can reject the null hypothesis at 5% of significance, and we can conclude that we have association between the two variables analyzed.

Step-by-step explanation:

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Assume the following dataset:

                           Amusement Parks     Mexico    Home    Other    Total

Freshman                     23                         21            43          21         108

Sophomore                  34                         23            14          26        97

Junior                           25                         30            23         26        104

Senior                           27                         33             17         19         96

Total                            109                        107            97         92        405

We need to conduct a chi square test in order to check the following hypothesis:

H0: There is independence between the two random variables

H1: There is dependence between the two variables

The level os significance assumed for this case is \alpha=0.05

The statistic to check the hypothesis is given by:

\chi^2 =\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}

The table given represent the observed values, we just need to calculate the expected values with the following formula E_i = \frac{total col * total row}{grand total}

And the calculations are given by:

E_{1} =\frac{109*108}{405}=29.07

E_{2} =\frac{107*108}{405}=28.53

E_{3} =\frac{97*108}{405}=25.87

E_{4} =\frac{92*108}{405}=24.53

E_{5} =\frac{109*97}{405}=26.11

E_{6} =\frac{107*97}{405}=25.63

E_{7} =\frac{97*97}{405}=23.23

E_{8} =\frac{92*97}{405}=22.03

E_{9} =\frac{109*104}{405}=27.99

E_{10} =\frac{107*104}{405}=27.48

E_{11} =\frac{97*104}{405}=24.91

E_{12} =\frac{92*104}{405}=23.62

E_{13} =\frac{109*96}{405}=25.84

E_{14} =\frac{107*96}{405}=25.36

E_{15} =\frac{97*96}{405}=22.99

E_{16} =\frac{92*96}{405}=21.81

And the expected values are given by:

                        Amusement Parks     Mexico    Home    Other    Total

Freshman                   29.07                28.53     25.87     24.53      108

Sophomore                26.11                  25.63     23.23     22.03      97

Junior                         27.99                 27.48     24.91      23.62     104

Senior                        25.84                 25.36     22.99      21.81       96

Total                            109                      107         97           92         405

And now we can calculate the statistic:

\chi^2 =27.356

Now we can calculate the degrees of freedom for the statistic given by:

df=(rows-1)(cols-1)=(4-1)(4-1)=9

And we can calculate the p value given by:

p_v = P(\chi^2_{9} >27.356)=0.00122

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(27.356,9,TRUE)"

Since the p value is lower than the significance level assumed 0.05 we can reject the null hypothesis at 5% of significance, and we can conclude that we have association between the two variables analyzed.

7 0
3 years ago
HELP ME ASAP! Will give BRAINLIEST! Please read the question THEN answer correctly! No guessing.
Goshia [24]

Answer:

D. Vertx: (3,-16); Intercepts: x = -1, 7

Step-by-step explanation:

I graphed the equation on the graph below.

5 0
3 years ago
A target has a bull’s-eye with a diameter of 2 inches. The outer ring is 1 inch wide. What is the area of the outer ring? A circ
Arturiano [62]

Answer:

<h2>it is option 2      3 Pi inches squared</h2>

Step-by-step explanation:

good job :)

7 0
3 years ago
Read 2 more answers
-6 &gt; -9<br><br> Which best explains whether the inequality is true or false?
Natali [406]

Answer:

-6 on a number line is closer to 0 which make sit greater while -9 is farther away which makes it less than -6

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
There were 200 people who voted at the Town council meeting all these people 40% voted for a new basketball court in the park ho
galben [10]

Answer:

120 people voted against building the new basketball court.

Step-by-step explanation:

if you divide 200 by 100 then you know how many people equal 1 percent of the 200. knowing that for every 2 people they are equal to 1 percent. so if you do 100 -40 you get 60. the 100 represents the 100 percent and you subtract 40 because these are the people who are voting for the basketball court. The 60 represents the percent of people who are voting against building the basketball court. then you multiply 60 by 2 and you get 120.

3 0
3 years ago
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