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Hitman42 [59]
2 years ago
6

Find for x , please its a emergency!!!

Mathematics
2 answers:
Igoryamba2 years ago
7 0

Answer:

45

Step-by-step explanation:

the left and right side are symetrical

Illusion [34]2 years ago
5 0

Answer:

x= 42

Step-by-step explanation:

All sides of a triangle add up to 180 degrees. To find the value of x, we can follow this simple equation:

A + B + C = 180 (Where the letters are the sides)

Lets say the A is the 45˚ and B is the 93˚. Then C can represent x and we can make an equation of:

45 + 93 + x= 180

138 + x = 180

138 - 138 + x= 180 - 138

x= 42

Check your work by plug in the value of x in the original equation:

45 + 93 + 42 = 180

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Find y.<br> 30<br> 20 <br> Need help asap
Neporo4naja [7]

Answer:

y = 10

Step-by-step explanation:

Using the sine ratio in the right triangle and the exact value

sin30° = \frac{1}{2} , then

sin30° = \frac{opposite}{hypotenuse} = \frac{y}{20} = \frac{1}{2} ( cross- multiply )

2y = 20 ( divide both sides by 2 )

y = 10

7 0
2 years ago
Diana bought a car for $5000 and plans to sell it to make a 20% profit. What should she sell it for to make the profit she desir
nalin [4]
You need to know 20% of $5000.  "Of" means "times".  

$5000 x 0.20 (which is 20% written as a decimal)

=$1000 profit she wants to make

$5000 (original price) + $1000 (profit) = $6000 (sale price)
4 0
3 years ago
Read 2 more answers
In triangle ABC, an altitude is drawn from vertex C to the line containing AB. The length of this altitude is h and h=AB. Which
adoni [48]

Answer:

II. Angle C cannot be a right angle.

III. Angle C could be less than 45 degrees.

4 0
3 years ago
Read 2 more answers
A metallurgist has an alloy with 5% titanium and an alloy with 30% titanium. He needs 100 grams of an alloy with 15% titanium. H
andrey2020 [161]
Let us convert the percentages to decimal format first.. so 5% is just 5/100 or 0.05 and 15% is just 15/100 or 0.15

so hmmm, so, let's say it needs "x" amount and "y" amount of each respectively, so, whatever "x" and "y" are, they must add up to 100, and whatever their concentration is, must add up to what the mixture yields

thus

\bf \begin{array}{lccclll}&#10;&amount&concentration&&#10;\begin{array}{llll}&#10;concentrated\\&#10;amount&#10;\end{array}\\&#10;&-----&-------&-------\\&#10;\textit{5\% alloy}&x&0.05&0.05x\\&#10;\textit{30\% alloy}&y&0.30&0.3y\\&#10;-----&-----&-------&-------\\&#10;mixture&100&0.15&15&#10;\end{array}&#10;\\\\\\&#10;\begin{cases}&#10;x+y=100\implies \boxed{y}=100-x\\&#10;0.05x+0.3y=15\\&#10;----------\\&#10;0.5x+0.3\left( \boxed{100-x} \right)=15&#10;\end{cases}

solve for "x"

what's "y"? well, y = 100 - x
4 0
3 years ago
<img src="https://tex.z-dn.net/?f=2x%28x%20-%202%29%5E%7B2%7D%20%20%2B%203x%28x%20%2B%203%29%5E%7B2%7D%20%20-%20x%5E%7B2%7D%20%2
Ratling [72]

= x·[2(x²- 4x + 4) + 3(x² + 6x + 9) - x² + 5x]

= x(2x² - 8x + 8 + 3x² + 18x + 27 - x² + 5x)

= x(4x² + 15x + 35)

5 0
3 years ago
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