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Jlenok [28]
3 years ago
6

Does the graph represent Y as a function of X?​

Mathematics
1 answer:
kompoz [17]3 years ago
4 0

Answer:

jsjshsiwiirtkkekwkuwhehhejwjwiid

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Solve the system of equations<br><br> 4x+3y=13<br> y=-x+4
Delvig [45]
4x+3y=13
y=-x+4
x+y=4
4x+3y=13
4x+4y=16
-y=-3
<em>y=3
</em>
<em />4x+9=13
4x=4<em>
x=1
hope i helped!!</em>
8 0
3 years ago
Since there are 640 acres of land in one section (1 mi2), how many acres of land are in a complete township?
Ne4ueva [31]

Answer:

9

Step-by-step explanation:

8 0
3 years ago
Find the partial fraction decomposition of the rational expression with prime quadratic factors in the denominator
SpyIntel [72]
\dfrac{5x^4-7x^3-12x^2+6x+21}{(x-3)(x^2-2)^2}=\dfrac{a_1}{x-3}+\dfrac{a_2x+a_3}{x^2-2}+\dfrac{a_4x+a_5}{(x^2-2)^2}
\implies 5x^4-7x^3-12x^2+6x+21=a_1(x^2-2)^2+(a_2x+a_3)(x-3)(x^2-2)+(a_4x+a_5)(x-3)

When x=3, you're left with

147=49a_1\implies a_1=\dfrac{147}{49}=3

When x=\sqrt2 or x=-\sqrt2, you're left with

\begin{cases}17-8\sqrt2=(\sqrt2a_4+a_5)(\sqrt2-3)&\text{for }x=\sqrt2\\17+8\sqrt2=(-\sqrt2a_4+a_5)(-\sqrt2-3)\end{cases}\implies\begin{cases}-5+\sqrt2=\sqrt2a_4+a_5\\-5-\sqrt2=-\sqrt2a_4+a_5\end{cases}

Adding the two equations together gives -10=2a_5, or a_5=-5. Subtracting them gives 2\sqrt2=2\sqrt2a_4, a_4=1.

Now, you have

5x^4-7x^3-12x^2+6x+21=3(x^2-2)^2+(a_2x+a_3)(x-3)(x^2-2)+(x-5)(x-3)
5x^4-7x^3-12x^2+6x+21=3x^4-11x^2-8x+27+(a_2x+a_3)(x-3)(x^2-2)
2x^4-7x^3-x^2+14x-6=(a_2x+a_3)(x-3)(x^2-2)

By just examining the leading and lagging (first and last) terms that would be obtained by expanding the right side, and matching these with the terms on the left side, you would see that a_2x^4=2x^4 and a_3(-3)(-2)=6a_3=-6. These alone tell you that you must have a_2=2 and a_3=-1.

So the partial fraction decomposition is

\dfrac3{x-3}+\dfrac{2x-1}{x^2-2}+\dfrac{x-5}{(x^2-2)^2}
7 0
4 years ago
Is the slope Positive, Negative, Zero or Undefined?<br><br> Find the slope<br> What does m=
wariber [46]

Answer:

Undefined

Step-by-step explanation:

3 0
3 years ago
A rectangle is reduced by a scale factor of One-fourth.
prohojiy [21]

Answer:

(\frac{4}{16})^2

\frac{12}{192}

(\frac{3}{12})^2

Step-by-step explanation:

we know that

If two figures are similar, the the ratio of its areas is equal to the scale factor squared

In this problem

The scale factor is 1/4

Let

z ---> the scale factor

x ---> the area of the smaller rectangle

y ---> the area of the large rectangle

so

z^2=\frac{x}{y}

we have

z=\frac{1}{4}

substitute

z^2=(\frac{1}{4})^2 =\frac{1}{16}

<u><em>Verify each option</em></u>

a) we have

\frac{4}{16}

Compare with  \frac{1}{16}

so

\frac{4}{16} \neq \frac{1}{16}

This option no show the ratio of the area of the smaller rectangle to the area of the larger rectangle

b) we have

(\frac{4}{16})^2=\frac{16}{256}=\frac{1}{16}

Compare with  \frac{1}{16}

so

\frac{1}{16} = \frac{1}{16}

This option show the ratio of the area of the smaller rectangle to the area of the larger rectangle

c) we have

\frac{12}{192}=\frac{1}{16}

Compare with  \frac{1}{16}

so

\frac{1}{16} = \frac{1}{16}

This option show the ratio of the area of the smaller rectangle to the area of the larger rectangle

d) we have

(\frac{4}{12})^2=\frac{16}{144}=\frac{1}{9}

Compare with  \frac{1}{16}

so

\frac{1}{9} \neq \frac{1}{16}

This option no show the ratio of the area of the smaller rectangle to the area of the larger rectangle

e) we have

(\frac{3}{12})^2=\frac{9}{144}=\frac{1}{16}

Compare with  \frac{1}{16}

so

\frac{1}{16} = \frac{1}{16}

This option show the ratio of the area of the smaller rectangle to the area of the larger rectangle

6 0
4 years ago
Read 2 more answers
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