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2 years ago

Scott walks to and from school each day. Each round trip is 3 kilometers long.

1 answer:

8 0

The equation that shows the relationship between the number of round trips, x and the number of kilometers, y Scott walked is y = 3x

Each round trip = 3 km

x = number of rounds

y = number of km he has walked in all.

1 rounds = 3 km

Therefore,

x rounds = 3x km

Each round of trip covers 3km. This means for each round of trip a distance of 3km is covered. The total distance or number of kilometers is represented with y.

The equation to show the relationship between x(number of rounds) and y (number of km) can be represented below

y = 3x

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Luden [163]

<h2>Answer = </h2><h2> $= \frac{1}{y {}^{5} x {}^{2} }$ </h2>

Step-by-step explanation:

Greetings !

simplify for variable y first

apply exponent rule

$a {}^{b} .a {}^{c} = a {}^{b +c \\ } \\ y {}^{ - 8}y {}^{5} = y {}^{ - 8 + 3}$

Add/subtract the numbers -8+3=5

$= y {}^{5}$

Apply exponent rule

$a {}^{ - b} = \frac{1}{a {}^{b} }$

Thus,

$y {}^{ - 5} = \frac{1}{y {}^{5} }$

secondly, simplify for the variable x

Apply exponent rule as we made on y

$x {}^{ - 2}$

$x {}^{ - 2} = \frac{1}{x {}^{2} }$

multiply bot the values we get

Hope it helps!

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A large truck and a small car have a head-on collision. Which scenario is true?

Nikolay [14]

The answer would be A

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2 years ago

Pete's checking account showed a balance at the beginning of the month of $180. After 3 days the checking account showed a balan

Cerrena [4.2K]

Answer:

180 - 172 =$8 8/3=2.56

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2 years ago

Find the surface area of the prism formed by the net

Lunna [17]

ANSWER

$T.S.A=1960m^2$

EXPLANATION

The diagram represents the net of a rectangular prism.

The dimensions are,

$l=42m$

$w = 14m$

and

$h = 7m$

The total surface area of a rectangular prism is given by:

$T.S.A=2(lw + lh + wh)$

We substitute the values to obtain,

$T.S.A=2(42 \times 14 + 42 \times 7 + 14 \times 7)$

$T.S.A=2(980)m^2$

$T.S.A=1960m^2$

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ohaa [14]

<h2>Answer:</h2><h2>-4</h2><h2 /><h2>Hope this helps!!</h2>

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