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3 years ago

What product did Britain continue to export despite objections by the Chinese government? silk fabric opium coal art.

SAT

2 answers:

Len [333]3 years ago

4 0

Answer:

Britain continued to export opium even though it was objected by Chinese government.

From the money that it got from exporting opium it financed it's tea imports from China.

Explanation:

Ksju [112]3 years ago

3 0

Answer:

opium

Explanation:

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Hoods become necessary any time water temperatures drop below: 20°C/68°F.

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3 years ago

Use the information above and the trigonometric identities to prove that Asin(wt

jenyasd209 [6]

Using sum and difference identities from trigonometric identities shows that; Asin(ωt)cos(φ) +Acos(ωt)sin(φ) = Asin(ωt + φ)

<h3>How to prove Trigonometric Identities?</h3>

We know from sum and difference identities that;

sin (α + β) = sin(α)cos(β) + cos(α)sin(β)

sin (α - β) = sin(α)cos(β) - cos(α)sin(β)

c₂ = Acos(φ)

c₁ = Asin(φ)

The Pythagorean identity can be invoked to simplify the sum of squares:

c₁² + c₂² =

(Asin(φ))² + (Acos(φ))²

= A²(sin(φ)² +cos(φ)²)

= A² * 1

= A²

Using common factor as shown in the trigonometric identity above for Asin(ωt)cos(φ) +Acos(ωt)sin(φ) gives us; Asin(ωt + φ)

Complete Question is;

y(t) = distance of weight from equilibrium position

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A = Amplitude

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2 years ago

Describe why a person is spending future income when using credit

liberstina [14]

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4 years ago

suppose you push a hockey puck of mass m across frictionless ice for a time 1.0 s, starting from rest, giving the puck speed v a

saul85 [17]

Answer: Twice the previous time would be taken to reach the same speed v with the puck of mass 2m.

Explanation:

Let a Force pushes the hockey puck of mass m.

Then acceleration, a= \frac{F}{m}a=mF

From the equation of motion,

\begin{gathered}\➪ v=u+at\\ v=0+\frac{F}{m}\Delta t\end{gathered}⇒v=u+atv=0+mFΔt ......(1)

In the second case, when mass is 2m, then acceleration,

a'=\frac{F}{2m}a′=2mF

and t' is the time taken.

The final speed is v,

\begin{gathered}\➪ v=0+ a't'\\ \➪ \frac {F}{m}\Delta t=\frac{F}{2m}t'\\ \➪ t'= 2\Delta t\end{gathered}⇒v=0+a′t′⇒mFΔt=2mFt′⇒t′=2Δt using equation (1)

Hence, it would take two times the previous amount of time to push the pluck of double mass.

 I hope this is understandable and if my answer helped you please can you give me a brainliest its will really help me and thank you have a nice day!!

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3 years ago

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