Question

Thre graph of a polynomial f(x)=(2x-3)(x-4)(x+3) has x-intercepts at 3 x values. what are they?

Answer 1

Answer:

3/2, 4 and -3.

Step-by-step explanation:

f(x)=(2x-3)(x-4)(x+3) = 0 at the x-intercepts.

So 2x-3 = 0, so x = 3/2

x-4=0, so x = 4

x+3=0, so x=- 3.