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Juliette [100K]
3 years ago
14

+00

Mathematics
1 answer:
PolarNik [594]3 years ago
5 0

Answe HINTTTTTTTTTTTTTTTTTTTTTTTT

Step-by-step explanation:

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Answer:     lise will play 2 times deanna will play 4 times                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                        

 

Step-by-step explanation:

6 0
4 years ago
A local animal rescue organization receives an average of 0.55 rescue calls per hour. Use the Poisson distribution to find the p
andreyandreev [35.5K]

Answer:

B) 0.894

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

A local animal rescue organization receives an average of 0.55 rescue calls per hour.

This means that \mu = 0.55

Probability that during a randomly selected hour, the organization will receive fewer than two calls.

P(X < 2) = P(X = 0) + P(X = 1)

In which

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-0.55}*(0.55)^{0}}{(0)!} = 0.577

P(X = 1) = \frac{e^{-0.55}*(0.55)^{1}}{(1)!} = 0.317

P(X < 2) = P(X = 0) + P(X = 1) = 0.577 + 0.317 = 0.894

5 0
4 years ago
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