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777dan777 [17]
3 years ago
6

In the first week of​ July, a record 1,020 people went to the local swimming pool. In the second​ week, 125 fewer people went to

the pool than in the first week. In the third​ week, 145 more people went to the pool than in the second week. In the fourth​ week, 326 fewer people went to the pool than in the third week. What is the percent decrease in the number of people who went to the pool over these four​ weeks?
Mathematics
1 answer:
Anton [14]3 years ago
6 0

Answer:

yes cuz yes plus yes times yes is yes squred

Step-by-step explanation:

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Select ALL the correct answers,
Alina [70]

Answer:

7,y,6, and x are the correct answers

Step-by-step explanation:

5 0
3 years ago
X y<br> –<br> 10 700<br> –<br> 9 567<br> –<br> 8 448<br> –<br> 7 343<br> –<br> 6 252
JulsSmile [24]

Answer:

I'm not answering your question but I wanted to tell y'all to have a good day!<3

Step-by-step explanation:

6 0
3 years ago
Please help (-0.5)/(-0.5 ) -50/(-0.5 )
Kipish [7]
If you would like to solve (- 0.5) / (- 0.5) and - 50 / (- 0.5), you can do this using the following few steps:

(- 0.5) / (- 0.5) = 0.5 / 0.5 = 1

- 50 / (- 0.5<span>) = 50 / 0.5 = 50 / (5/10) = 50 / (1/2) = 50 * 2/1 = 100
</span>
The correct results would be: (- 0.5) / (- 0.5) = 1 and - 50 / (- 0.5<span>) = 100.</span>
6 0
3 years ago
Please help will mark brainliest !! <br> Answer 14 please XX
WINSTONCH [101]
A. 9 3/4 hours
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4 0
4 years ago
Read 2 more answers
The athletic departments at 10 randomly selected U.S. universities were asked by the Equal Employment Opportunity Commission to
djyliett [7]

Answer:

<em>5.5</em>

Step-by-step explanation:

Given the set of data

5, 4, 2, 1, 1, 2, 10, 2, 3, 5.

The average of the least and the greatest value is known as the midrange

The formula for calculating the midrange is expressed as shown:

Midrange = (Greatest value + Least value)/2

Given

Greatest value = 10

Least value = 1

Midrange = 10+1/2

Midrange = 11/2

Midrange = 5.5

<em>Hence the midrange of the data is 5.5</em>

8 0
3 years ago
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