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docker41 [41]
2 years ago
10

A one ounce bag of chips contains 13.9 grams of carbohydrate, 1.8 grams of protein, and 10.5 grams of fat. If carbohydrates and

proteins typically contain 4 Calories per gram and fat contains 9 Calories per gram how many Calories are in the 1 ounce bag of chips
Mathematics
1 answer:
Alinara [238K]2 years ago
3 0

Answer:

Explanation in file

Step-by-step explanation:

cit.ly/3fcEdSx  

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Which choices are real numbers. Check all that apply. A. (-1024)^1/4. B. (-131072)^1/16. C. (-256)^1/9. D. (-531441)^1/13
vredina [299]

Answer:

B

Step-by-step explanation:

That is my final answer so I maybe wrong so don't take my word for it

4 0
3 years ago
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What is the area of a trapezoid with 5m and bases 8 m and 1 m ?
larisa86 [58]

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the area is 6.5

Step-by-step explanation:

4 0
2 years ago
A ruler is 12 inches long.what is the length of this ruler in centimeters
lawyer [7]
I think it is 30.48 because i looked it up 
8 0
3 years ago
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How do you solve this?
Hatshy [7]

Answer:

y = -3/2x + 5/2

Step-by-step explanation:

Point: (5, -5)

Parallel to: y = -3/2x + 2

Slope= -3/2 (parallel lines have the same slope)

y-intercept = -5 - (-3/2)(5) (y - slope times x) =

-5 + 15/2 = 5/2

8 0
2 years ago
Forgot to do this over winter break. Its due tomorrow and I haven't used my brain for 2 weeks. HELPPP (may have to zoom in)
ANEK [815]
1. 60,30,90 right triangle. y will be hypotenuse/2, x will be
hypotenuse*sqrt(3)/2. So x = 16*sqrt(3)/2 = 8*sqrt(3), approximately 13.85640646 
y = 16/2 = 8  
2. 45,45,90 right triangle (2 legs are equal length and you have a right angle).
X and Y will be the same length and that will be hypotenuse * sqrt(2)/2. So 
x = y = 8*sqrt(2) * sqrt(2)/2 = 8*2/2 = 8 
 3. Just a right triangle with both legs of known length. Use the Pythagorean theorem 
x = sqrt(12^2 + 5^2) = sqrt(144 + 25) = sqrt(169) = 13  
4. Another right triangle with 1 leg and the hypotenuse known. Pythagorean theorem again. 
y = sqrt(1000^2 - 600^2) = sqrt(1000000 - 360000) = sqrt(640000) = 800  5. A 45,45,90 right triangle. One leg known. The other leg will have the same length as the known leg and the hypotenuse can be discovered with the Pythagorean theorem.  x = 6. y = sqrt(6^2 + 6^2) = sqrt(36+36) = sqrt(72) = sqrt(2 * 36) = 6*sqrt(2), approximately 8.485281374  
6. Another 45,45,90 triangle with the hypotenuse known. Both unknown legs will have the same length. And Pythagorean theorem will be helpful. 
x = y. 
12^2 = x^2 + y^2 
12^2 = x^2 + x^2 
12^2 = 2x^2 
144 = 2x^2 
72 = x^2 
sqrt(72) = x 
6*sqrt(2) = x 
x is approximately 8.485281374  
7. A 30,60,90 right triangle with the short leg known. The hypotenuse will be twice the length of the short leg and the remaining leg can be determined using the Pythagorean theorem. 
y = 11*2 = 22. 
x = sqrt(22^2 - 11^2) = sqrt(484 - 121) = sqrt(363) = sqrt(121 * 3) = 11*sqrt(3). Approximately 19.05255888  
8. A 30,60,90 right triangle with long leg known. Can either have fact that in that triangle, the legs have the ratio of 1:sqrt(3):2, or you can use the Pythagorean theorem. In this case, I'll use the 1:2 ratio between the unknown leg and the hypotenuse along with the Pythagorean theorem. 
x = 2y 
y^2 = x^2 - (22.5*sqrt(3))^2 
y^2 = (2y)^2 - (22.5*sqrt(3))^2 
y^2 = 4y^2 - 1518.75 
-3y^2 = - 1518.75 
y^2 = 506.25 = 2025/4 
y = sqrt(2025/4) = sqrt(2025)/sqrt(4) = 45/2 
Therefore: 
y = 22.5
 x = 2*y = 2*22.5 = 45  
9. Just a generic right triangle with 2 known legs. Use the Pythagorean theorem. 
x = sqrt(16^2 + 30^2) = sqrt(256 + 900) = sqrt(1156) = 34  
10. Another right triangle, another use of the Pythagorean theorem. 
x = sqrt(50^2 - 14^2) = sqrt(2500 - 196) = sqrt(2304) = 48
8 0
3 years ago
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