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Mrrafil [7]
2 years ago
13

Directions: Tell whether the following is a quadratic inequality or not.

Mathematics
1 answer:
Leya [2.2K]2 years ago
6 0

Anser

(b2 – 4ac). sorry if this doesnt help it doesnt make sense on my screen it shows a weird equation

Step-by-step explanation:

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Find the third term of (x^2 + 2)^4.
attashe74 [19]

Answer:

Step-by-step explanation:

in~the~expansion~of~(x+a)^n\\T_{r+1}=ncr x^{n-r}a^r\\r+1=3\\r=3-1=2\\n=4\\4c2=\frac{4 \times 3}{2 \times 1} =6\\T_{2}=4(x^2)^{4-2}(2)^2\\=16(x^2)^2\\=16x^4

7 0
3 years ago
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4 friends share 3 oranges equally. How much does each friend get?
saveliy_v [14]
3 oranges / 4 friends  =  3/4 orange for each of them, or 0.75 orange each

(You can check the answer by saying, if each of them get 3/4 of an orange, then multiplying that by the 4 friends should give me the 3 oranges.  3/4 x 4 = 3, so it's correct).
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3 years ago
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To convert 8 kiloliters to liters, the first ratio is 1 kL/1,000 L. To set up the proportion, the second ratio must be _____.
My name is Ann [436]
It would be b. the first ratio is
1kL
----
1000

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6 0
3 years ago
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An article estimates, with 90% confidence, that the proportion of elementary school teachers who are female is 82%. The article
GREYUIT [131]

Answer:   (80% , 85%)

Step-by-step explanation:

We know that, confidence interval for population proportion is given by :-

(p-E , p+E)

, where p = sample proportion , E = Margin of error.

Given : Proportion of elementary school teachers who are female = 82%.

The article also states the maximum error of their estimate = 3%.

Then, the 90% confidence interval for the proportion of elementary school teachers who are female will be :

(82%-2% , 82%+3%)

= (80% , 85%)

Hence, the resulting 90% confidence interval for the proportion of elementary school teachers who are female = (80% , 85%)

5 0
3 years ago
3,408 divided by 41 <br><br> Explanation in traditional method<br><br><br><br> 52 POINTS PLS HELP
Furkat [3]

Answer:

83.1219512195

Step-by-step explanation:

Hope this helps!

7 0
2 years ago
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