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zvonat [6]
3 years ago
13

%20%5C%3A%20fre%7D%7D%7D%7D" id="TexFormula1" title="\huge\blue{\boxed{\tt{\colorbox{black}{hi need kausap \: who \: fre}}}}" alt="\huge\blue{\boxed{\tt{\colorbox{black}{hi need kausap \: who \: fre}}}}" align="absmiddle" class="latex-formula">
FRĚĚ POINTS PO

​
Mathematics
2 answers:
mars1129 [50]3 years ago
6 0
What???????? Lol I don’t get it
-Dominant- [34]3 years ago
6 0

Answer:

oh ito gawan kita Sana magustuhan mo haha sorry kung panget

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Lelu [443]
 109 \div 8 

= 13.625
7 0
3 years ago
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Someone please help me with these Geometry questions.
AnnZ [28]
<h3>Answer: 112.5 square units</h3>

Work Shown:

A = area of the triangle

A = base*height/2

A = 9*7/2 = 63/2 = 31.5 ... see note1 below

B = area of rectangle

B = base*height

B = 9*3 = 27

C = area of parallelogram

C = base*height .... see note2 below

C = 9*6 = 54

If you're confused where I got the 6 from, check out the attached image below.

D = total area of the composite figure

D = A+B+C

D = 31.5 + 27 + 54

D = 112.5

-------------------------

note1: The vertical component of the triangle is 9 units because this is part of the rectangle. The rectangle has opposite sides that are the same length. The parallelogram's vertical sides are 9 units long as shown by the single tickmark.

note2: a rectangle is essentially a special case of a parallelogram. In other words, a rectangle is a parallelogram with 4 right angles. So this is why the formula "area = base*height" shows up identical for both rectangles and parallelograms. Keep in mind that the height is always perpendicular to the base. You will not use the segments marked with double tickmarks.

6 0
3 years ago
Find the value of x in each case.
Tatiana [17]

Answer:

• First pic

{ \tt{4x + 65 \degree + x = 180 \degree}} \\  \dashrightarrow \: { \sf{ \{angles \: on \: straight \: line \}}} \\  \\ { \tt{5x + 65 \degree = 180 \degree}} \\  \\ { \tt{5x = 180 \degree - 65 \degree}} \\  \\ { \tt{x =  (\frac{115}{5} ) \degree}} \\  \\  \dashrightarrow \: { \boxed{ \tt{ \:  \: x = 23 \degree \:  \: }}}

• Second pic:

{ \tt{(180 \degree - 124 \degree) + 2x = 6x}} \\  \dashrightarrow \: { \sf{ \{interior \: angle \: sum equivexterior \: angle \} }} \\  \\  { \tt{56 \degree = 6x - 2x}} \\  \\ { \tt{4x = 56 \degree}} \\  \\ { \tt{x = ( \frac{56}{4} ) \degree}} \\  \\  \dashrightarrow \: { \boxed{ \tt{x = 14 \degree}}}

8 0
2 years ago
Read 2 more answers
Find the area of semi-circle whose radius is 'm' units.​
Sav [38]
  • Radius of the circle = m units
  • Therefore, area of the circle = \pi \:  {m}^{2} square \:  \: units
  • We know, semi-circle is half of a circle.
  • So, the area of the semi-circle =  \frac{\pi \:  {m}^{2} }{2}  \: square\:  \: units

<u>Answer</u><u>:</u>

<u>\frac{\pi \:  {m}^{2} }{2}  \: square\:  \: units</u>

Hope you could understand.

If you have any query, feel free to ask.

7 0
3 years ago
Plot the points P (2, -3) &amp; Q (-5, -3) whose ordinates are same. To which axis the line PQ is parallel.
Nadya [2.5K]

Given :

The points P (2, -3) & Q (-5, -3) whose ordinates are same.

To Find :

To which axis the line PQ is parallel.

Solution :

In given points the ordinates are same.

Therefore, the line is parallel to the x- axis.

Hence, this is the required solution.

5 0
3 years ago
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