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3 years ago

Numeros comprendidos entre 20

1 answer:

8 0

One, two, three, four, five, six, seven, eight, nine, ten, eleven, twelve, thirteen, fourteen, fifteen, sixteen, seventeen, eighteen, and nineteen/Uno, dos, tres, cuatro, cinco, seis, siete, ocho, nueve, diez, once, doce, trece, catorce, quince, dieciséis, diecisiete, dieciocho y diecinueve

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3 (x+2)+9<6(x-3) solve the inequality and write the solution using interval notation

Darya [45]

Answer:

(11, ∞).

Step-by-step explanation:

3 (x+2)+9<6(x-3)

3x + 6 + 9 < 6x - 18

-3x < -18 - 6 - 9

-3x < -33

x > 11 (Note the inequality flips as we are dividing by a negative value).

6 0

3 years ago

The area of a trapezoid is 60 square inches. One of the bases is 8 inches long. The height is 6 inches long. What is the length

Mashcka [7]

Answer:

12 in

Step-by-step explanation:

The area (A) of a trapezoid is calculated as

A = $\frac{1}{2}$ h(b₁ + b₂ )

where h is the height and b₁, b₂ the parallel bases

Given h = 6, b₁ = 8 and A = 60 , then

$\frac{1}{2}$ × 6 × (8 + b₂ ) = 60 , that is

3(8 + b₂ ) = 60 ( divide both sides by 3 )

8 + b₂ = 20 ( subtract 8 from both sides )

b₂ = 12

The length of the second base is 12 inches

6 0

3 years ago

If f(x)=x and g(x) =2, what is (f•g)(x)

slavikrds [6]

The answer is c. You distribute the X to the F and G. f(x) + g(x), which is x + 2.

7 0

3 years ago

To solve problems about spans of time that include B.C. and A.D. dates, you would need to use which numbers?

Studentka2010 [4]

The correct numbers to use in solving problems about spans of time like B.C. and A.D. should be “integers”.

Integers are whole numbers (not a fractional number or not a decimal number) which can take a value of negative, zero, or positive number. Example of integers would be -1, 0 and 1.

<span>In calculations, the time period would be on the x-axis. Since B.C. and A.D. are two different spans of time, therefore in the calculations, the date of BC should be negative (negative x-axis) while the date of AD should be positive (positive x-axis). This would place the origin as the common reference.</span>

3 0

3 years ago

Suppose we have two binomial populations where the true proportion of success is .2 for the first population and .3 for the seco

Veseljchak [2.6K]

Answer:

The value is not close to 0.3 because of sampling variability.

Step-by-step explanation:

The group of answer choices are not given which are as follows:

All of the above
Because the sample size is too small
Because of sampling variability
Because of nonresponse bias

From this the correct option is option C which is Because of Sampling Variability.

This is true because the two populations are of different values and thus the sample is not dependent on any one of the two possibilities. When a sample of 4 is considered from first and 400 from the second the overall probability will be far from the value of 0.3. So the

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3 years ago