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OverLord2011 [107]
3 years ago
14

Anton will be constructing a segment bisector with a compass and straightedge, while Maxim will be constructing an angle bisecto

r with a compass and straightedge. Describe the similarities and differences between their construction steps.
Mathematics
1 answer:
elena-14-01-66 [18.8K]3 years ago
3 0

A bisector is a line that divides either a line or an angle into <em>two</em><em> proportionate</em> parts or angles. Thus, Anton's <em>bisector</em> would divide the segment into two <u>equal parts</u>, while Maxim's <em>bisector</em> would divide the angle into two <u>equal angles</u>.

The <u>similarities</u> between their construction are:

  • <em>Intersecting</em> arcs through which the bisector would pass are required.
  • The arcs are dawn using <em>the same</em> radius of any measure.
  • The <em>edges</em> of the arc of the given angle, and the ends of the segment are used as <em>centers</em>.

The <u>differences</u> between their construction are:

  • Anton has to draw two intersecting arcs <u>above</u> and <u>below</u> the segment. While Maxim would draw two intersecting arcs <u>within</u> the lines forming the angles.
  • Anton's bisector would be <em>perpendicular</em> to the segment, while Maxim's bisector would be at <em>an angle</em> which is half of the initial angle.

Visit: brainly.com/question/17247176

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11.1 units

Step-by-step explanation:

We solve for this using the formula when using coordinates (x1 , y1) and (x2, y2)

= √(x2 - x1)² + (y2 - y1)²

A(5,2), B(5,4), and C(1,1).

For AB = √(x2 - x1)² + (y2 - y1)²

= A(5,2), B(5,4)

= √(5 - 5)² +(4 - 2)²

= √ 0² + 2²

= √4

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For BC = √(x2 - x1)² + (y2 - y1)²

= B(5,4), C(1,1)

= √(1 - 5)² +(1 - 4)²

= √ -4² + -3²

= √16 + 9

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For AC = √(x2 - x1)² + (y2 - y1)²

A(5,2), C(1,1)

= √(1 - 5)² + (1 - 2)²

= √-4² + -1²

= √16 + 1

= √17

= 4.1231056256 units

The Formula for the Perimeter of Triangle = Side AB + Side BC + Side AC

= 2 units + 5 units + 4.1231056256 units

= 11.1231056256 units.

Approximately the Perimeter of a Triangle to the nearest tenth = 11.1units

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