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OverLord2011 [107]
2 years ago
14

Anton will be constructing a segment bisector with a compass and straightedge, while Maxim will be constructing an angle bisecto

r with a compass and straightedge. Describe the similarities and differences between their construction steps.
Mathematics
1 answer:
elena-14-01-66 [18.8K]2 years ago
3 0

A bisector is a line that divides either a line or an angle into <em>two</em><em> proportionate</em> parts or angles. Thus, Anton's <em>bisector</em> would divide the segment into two <u>equal parts</u>, while Maxim's <em>bisector</em> would divide the angle into two <u>equal angles</u>.

The <u>similarities</u> between their construction are:

  • <em>Intersecting</em> arcs through which the bisector would pass are required.
  • The arcs are dawn using <em>the same</em> radius of any measure.
  • The <em>edges</em> of the arc of the given angle, and the ends of the segment are used as <em>centers</em>.

The <u>differences</u> between their construction are:

  • Anton has to draw two intersecting arcs <u>above</u> and <u>below</u> the segment. While Maxim would draw two intersecting arcs <u>within</u> the lines forming the angles.
  • Anton's bisector would be <em>perpendicular</em> to the segment, while Maxim's bisector would be at <em>an angle</em> which is half of the initial angle.

Visit: brainly.com/question/17247176

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-0.9

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-9/ 10 = -0.9

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8) Find the endpoint Cif M is the midpoint of segment CD and M (2, 4) and D (5,7)
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Answer:

8. c. (-1, -1)

9. a. (-6, -1)

b. True

Step-by-step Explanation:

8. Given the midpoint M(2, 4), and one endpoint D(5, 7) of segment CD, the coordinate pair of the other endpoint C, can be calculated as follows:

let D(5, 7) = (x_2, y_2)

C(?, ?) = (x_1, y_1)

M(2, 4) = (\frac{x_1 + 5}{2}, \frac{y_1 + 7}{2})

Rewrite the equation to find the coordinates of C

2 = \frac{x_1 + 5}{2} and 4 = \frac{y_1 + 7}{2}

Solve for each:

2 = \frac{x_1 + 5}{2}

2*2 = \frac{x_1 + 5}{2}*2

4 = x_1 + 5

4 - 5 = x_1 + 5 - 5

-1 = x_1

x_1 = -1

4 = \frac{y_1 + 7}{2}

4*2 = \frac{y_1 + 7}{2}*2

8 = y_1 + 7

8 - 7 = y_1 + 7 - 7

1 = y_1

y_1 = 1

Coordinates of endpoint C is (-1, 1)

9. a.Given segment AB, with midpoint M(-4, -5), and endpoint A(-2, -9), find endpoint B as follows:

let A(-2, -9) = (x_2, y_2)

B(?, ?) = (x_1, y_1)

M(-4, -5) = (\frac{x_1 + (-2)}{2}, \frac{y_1 + (-9)}{2})

-4 = \frac{x_1 - 2}{2} and -5 = \frac{y_1 - 9}{2}

Solve for each:

-4 = \frac{x_1 - 2}{2}

-4*2 = \frac{x_1 - 2}{2}*2

-8 = x_1 - 2

-8 + 2 = x_1 - 2 + 2

-6 = x_1

x_1 = -6

-5 = \frac{y_1 - 9}{2}

-5*2 = \frac{y_1 - 9}{2}*2

-10 = y_1 - 9

-10 + 9 = y_1 - 9 + 9

-1 = y_1

y_1 = -1

Coordinates of endpoint B is (-6, -1)

b. The midpoint of a segment, is the middle of the segment. It divides the segment into two equal parts. The answer is TRUE.

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