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masha68 [24]
3 years ago
5

4.5 x 30 = tenths x 30 =

Mathematics
1 answer:
Ira Lisetskai [31]3 years ago
3 0

Answer:

4.5 x 30 = 135

0.1 x 30 = 3

Hint: something multiplied by 0.1 is the same as that same thing divided by 10.

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Solve for x.<br> 3x - 161<br> 7x - 382
vivado [14]

Answer:

55.25 = x

Step-by-step explanation:

3x - 161 = 7x - 382

Balance method:

7x- 3x = -161 + 382

4x = 221

Divide to find x:

221/4 = x

55.25 = x

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3 years ago
Leon tried to solve an equation step by step.
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Step-by-step explanation:

in step 2 leon made mistake

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Which triangle is a translation of triangle P?
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Step-by-step explanation:

I did the quiz

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3 years ago
What are the methods of substitution?
anyanavicka [17]

Answer:

-<u>One Equation</u>: is set equal to a variable

Example:

y = 2x + 1

x + 3y = -12

You already have y, plug it back into x + 3y = -12

x + 3(2x + 1) = -12

x + 6x + 3 = -12

7x + 3 = -12

(Subtract 3 from each side)

7x = -15

(Divide by 7)

x = - 2.14

-<u>No Equation</u>: is set equal to a variable

Example:

2x + y = 10

4× + 2y = -3

Subtract 2x from each side of 2x + y = 10, you should get y= -2x + 10. Now that you have found y, substitute y into 4x+ 2y = -3.

4x + 2(-2x + 10) = -3

4x + -4x + 20 = -3

(Subtract 20 from each side)

4x + -4x = -23

(Add 4x and -4x)

0 = -23

No Solution

<u>-Both</u><u> </u><u>Equations</u>: are set equal to a variable

Example:

y = x + 5

y = -x + 3

(you already have y so plug it into the other equation to solve for x)

-x + 3 = x + 5

(Add -x on both sides)

3 = 2x + 5

(subtract 5 from both sides)

-2 = 2x

(Divide by 2 on each side)

x = -1

I hope this helped!

8 0
3 years ago
Let R be the triangular region in the first quadrant, with vertices at points (0,0), (0,2), and (1,2). The region R is the base
s2008m [1.1K]

The line through (0, 0) and (1, 2) has equation y=2x.

Each cross section has a leg in the xy-plane whose length is the horizontal distance from the y-axis to the line y=2x, which is x=\frac y2.

The cross sections are isosceles right triangles, so the legs that lie perpendicular to the xy-plane have the same length as the legs *in* the xy-plane, hence these triangles haves bases and heights equal to \frac y2. Then the area of each cross section is

\dfrac12\left(\dfrac y2\right)^2=\dfrac{y^2}8

where the cross sections are generated over the interval 0\le y\le2.

The volume of the solid is then

\displaystyle\int_0^2\frac{y^2}8\,\mathrm dy=\frac1{24}y^3\bigg|_0^2=\frac{2^3}{24}=\frac13

8 0
3 years ago
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