3 years ago

Find the possible values of the constant

Mathematics

1 answer:

andreev551 [17]3 years ago

5 0

Step-by-step explanation:

x - (k+2)x + 4

Since the roots are equal, b^2 - 4ac =0

a =x, b=k+2, c =4

(k+2)^2 - 4(1×4) =0

K^2 + 4k + 4-16 =0

K^2 +4k - 12=0

K^2 +6k - 2k - 12 =0

K(k + 6) - 2(k +6)=0

(k-2)(k +6) =0

K =2 or - 6

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