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trasher [3.6K]
3 years ago
5

Pythagoras theorem Please answer will mark BRAINELIST :)

Mathematics
1 answer:
Mumz [18]3 years ago
6 0

Answer:

Step-by-step explanation:

Since we are to show by Pythagoras that  the square will fit inside the circle without touching the edge of the circle , this means that we must find the value of the length of the diagonal of the square using Pythagoras.

For the square to fit in without touching the edge of the circle , this means that the diagonal of the square must be less than the diameter of the circle.

Length of the square is 5cm.

Recall Pythagoras theorem: it states that

the square on the hypotenuse of a right-angled triangle is equal in area to the sum of the squares on the other two sides

=  +

= 25 + 25

= 50

Take the square root of both sides , that is

D =

D =  X  , since 50 = 25 x 2

D = 5

D ≈ 7.07

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Choose the correct simplification of the expression 16 over n to the negative third power. n to the third power over 16 16 over
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Answer:

{16n}^{3}

Step-by-step explanation:

We want to simplify:

\frac{16}{ {n}^{ - 3} }

To simplify this, we need to write the negative index as positive.

So we use the property,

\frac{1}{ {a}^{ - n} }  =  {a}^{n}

When we apply this property, we get:

\frac{16}{ {n}^{ - 3} }  = \: 16 \times \frac{1}{ {n}^{ - 3} }  =16 {n}^{3}

Therefore the fourth option is correct.

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4 years ago
Pandas: There is a well-studied panda population in Wuyipeng. In 1981 there were 25 pandas and the researchers determined that t
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<h3>What models the data?
</h3>

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4 years ago
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Solve appropriate word problems by modeling them with linear equations in two variables.
Nesterboy [21]

<em><u>The cost of production equation is:</u></em>

C = 10n + 20000

<em><u>Solution:</u></em>

<em><u>The equation representing the cost, C, of producing n tires at Royal Tires Co. can be written as:</u></em>

C = mn + f

Where,

C = cost

n = number of tires

f = company's fixed cost

<em><u>It costs $30,000 to produce 1,000 tires while it costs $50,000 to produce 3,000 tires</u></em>

Therefore,

30, 000 = m(1000) + f

50, 000 = m(3000) + f

Which is,

1000m + f = 30000 ------- eqn 1

3000m + f = 50000 ------- eqn 2

Subtract eqn 1 from eqn 2

3000m + f = 50000

1000m + f = 30000

( - ) -------------------

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m = 10

Substitute m = 10 in eqn 1

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