The nearest neighbor technique doesn’t change any of the values from the input raster data set. It takes the cell center from the input raster data set to determine the closest cell center of the output raster. For processing speed, it’s generally the fastest because of its simplicity.
1. Any elevated area, such as mountain or an upland, separated two drainage basin such an elevation is known as a water divide—for example, Indus and the Ganga river. The high mountain or plateaus region where the water of the river flows in two opposite direction.
2. Ganga basin
3. The "origin of the Indus" and "Ganges river" is at "Himalayan Mountains".
4. The Ganga has two main headstreams are Bhagirathi and Alaknanda. They both meet to form the Ganga at Devprayag.
5. In Tibet, the river carries a smaller volume of water and less silt, as it is a cold and dry area. Hence, the river carries a large volume of water and a considerable amount of silt.
6. River Narmada and Tapi are the two Peninsular rivers which flow through trough.
7. Rivers and lakes are of a great value to human beings. They help to develop hydel power, provide water for irrigation, drinking, industries and they help to develop fisheries. They will enhance natural beauty and help in the development of tourism and provide recreation.
Hope this helped!
Answer:
I, II, and IV
Explanation:
"Race" is not an answer as it means "Ethnicity".
Ethnicity can be simply described as a person's identification in related to a certain group of peoples with a certain value system, culture and language.
In this case, all, the speaking language, cultural traditions and the shared common history identifies one group of people from another.
Answer: at the equator the normal force will be 3.4N less and at the North Pole = 980N
Explanation:
So, we will start the Calculation by considering the equation below;
Fnet = F(g) - F(N); where Fnet = mv^2/ r.
Hence, F(g) - F(N) = mv^2/ r -------------(1).
Making F(N) the subject of the formula, we have;
F(N) = Gm1m2/r^2 - mv^2/r.
Thus, we have;
Gm1m2/r^2 = 6.68 × 10^-11 × (5.98 × 20^24) × 100/ 6.38 × 10^6 = 980N.
Also, we have;
mv^2/r = m4π^2r/T^2.
100 × 6.38 ×10^6 × 4π^2/(24 × 3600)^2 = 3.4N
Therefore, at the equator the normal force will be 3.4N less and at the North Pole = 980N.
I think its called observational learning
(If i get this wrong Im srry)
