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Alla [95]
3 years ago
11

IM GIVING 40 POINTS PLEASEEEEE

Mathematics
1 answer:
Mars2501 [29]3 years ago
7 0

Answer:

Answer is $110.25. You figure out how.

Step-by-step explanation:

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What is the range of the function in the graph?
Anon25 [30]
Locate the highest or lowest point on the graph. In this case, there is no highest point. There is only the lowest point. That lowest point is (2,0). 

The y coordinate of that lowest point is y = 0. This is the smallest y can be. The value of y cannot be any smaller. This forms the left boundary of the interval notation answer.

There is no upper boundary on how high y can go. It can grow forever. Therefore the right boundary of the interval is infinity

This is why the answer is the interval notation answer [0,\infty)
The square bracket indicates "include this value in the set" while a parenthesis says "exclude this value". We can never reach infinity so infinity is always with a parenthesis

Final Answer: Choice A

Note: the interval notation answer for choice A is the same as writing y \ge 0 (y is greater than or equal to 0)
8 0
4 years ago
The sum of twice a number and 6 is 28
avanturin [10]
The answer for your question is 2(x+6)=28
4 0
4 years ago
Help ill give brainly!!!!!!!!!!!!!!!!
sp2606 [1]

Answer:

6(3x+4y)
18x+24y

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
How do you simplify 10 square root 96
cupoosta [38]
10 * √96

10 * √(16 * 6)

10 * √16 * √6

10 * 4 * √6

40 * √6

40√6
5 0
4 years ago
PLEASE HELP!!!!! What values complete each statement? Enter your answers in the boxes. (16‾‾‾√)2 = _ in simplest form. By the Po
mario62 [17]

We are given expression: (\sqrt{16})^2.

Square root in exponent form is power \frac{1}{2}.

Therefore, \sqrt{16} = 16^{1/2}.

Now, replacing square root of 16 by 16^{1/2} in original expression we are given, we get

(\sqrt{16})^2 = (16^{1/2})^2 = (16)^2/2 = 16.

Therefore,

<h3> (\sqrt{16})^2= 16 in simplest form. By the Power of Power rule, (16^{1/2})^2=16^{2/2} . So, 16^{1/2} must equal\sqrt{16} in radical form.</h3>
8 0
4 years ago
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