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Mandarinka [93]
2 years ago
15

What mass of glucose (C6H12O6) should be dissolved in 12. 0 kg of water to obtain a solution with a freezing point of -5. 8 ∘C?.

SAT
2 answers:
bogdanovich [222]2 years ago
8 0

The mass of glucose solute dissolved in the solution is 6.739 Kg.

Recall that;

ΔT = K m i

ΔT = Freezing point depression

K =Freezing point depression constant = 1.86°C/mol

m = molality of the solution

i = Van't Hoff factor = 1 (molecular solution)

We have to find the freezing point depression from;

Freezing point depression = Freezing point of pure solvent - Freezing point of solution

Freezing point of pure water = 0°C

Freezing point of solution = -5. 8 ∘C

Freezing point depression = 0°C - (-5. 8 ∘C) = 5. 8 ∘C

Now;

m = ΔT/K i

m = 5. 8 ∘C/ 1.86°C/mol × 1

m = 3.12 m

But molality = number of moles of solute/mass of solvent in Kg

Molar mass of solute = 180 g/mol

Let the mass of solute be m

3.12 = m/180/12

3.12 = m/180 × 12

m = 3.12 × 180 × 12

m = 6739 g or 6.739 Kg

Learn more: brainly.com/question/6249935

S_A_V [24]2 years ago
8 0

Answer:

6.7 kg

Explanation:

(0) - (-5.8)= 5.8ºC

5.8 / 1.86 = 3.12 m C6 H12 O6

The molar mass of C6 H12 O6 is: 180.156 g/mol

3.12 * 12 kg * 180.156 g/mol = 6,745.041 g = 6.7 kg.

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The statement Certain noteheads can only be placed on staff lines is: "False.

<h3>What is noteheads?</h3>

Noteheads can be placed on staff lines or in the spaces between them. The position of the notehead determines the pitch of the note. A notehead on a line or space corresponds to a specific letter name (A, B, C, D, E, F, or G) and octave (the range of pitches from one C to the next C).

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Sometimes, noteheads need to be placed above or below the staff to indicate higher or lower pitches. In this case, ledger lines are used to extend the staff. A ledger line is a short horizontal line that acts as a staff line for a single note. A notehead can be placed on a ledger line or in the space between ledger lines.

For example, in the treble clef, the notehead on the first ledger line above the staff is an A, and the notehead in the space above it is a B. The notehead on the second ledger line above the staff is a C, and the notehead in the space above it is a D.

Here is an example of noteheads on staff lines, in spaces, and on ledger lines in the treble clef:

D

 ---

C |   |

 ---

B |   |

 ---

A |   |

 ---

G |   |

 ---

F |   |

 ---

E |   |

 ---

 E F G A B C D

"

Therefore the statement is false.

Learn more about Noteheads  here:brainly.com/question/29871741

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