Answer:
Amount of money Judy has in her account is 
.
Amount of money Tommy has in his account is 
Step-by-step explanation:
To find : Amount of money in Judy account and amount of money in Tommy account:
Solution:
Given:
Judy has $7500 more than a number in her account.
Let the number be 'n'.
So we can say that;
Amount of money in Judy account is equal to 7500 plus number.
framing in equation form we get;
Amount of money in Judy account =
Hence Amount of money Judy has in her account is .
Now Given:
Tommy has 6 more than 3 times the amount of money in his bank account than Judy.
So we can say that;
Amount of money in Tommy account is equal to 3 multiplied by Amount of money in Judy account plus 6.
framing in equation form we get;
Amount of money in Tommy account = 
Hence Amount of money Tommy has in his account is .
cannot be changed to a mixed number. 10 could divide both numerator and denominator. And you get 2.
Answer:
y = 0.008x^2 + 0.518x + 131.886
Step-by-step explanation:
- Make sure your Plot 1 is ON. Select the Scatter Plots and the appropriate lists.
- Clear all functions in [Y=]
- Input data in L1 and L2. Go to [Stat] [Enter] to input data.
- Graph data points. ...
- Choose a regression from the list in [Stat] "CALC". ...
- Go to [ZOOM] "9: ZoomSTat" to view the data with the regression curve.
(credit: CPM Educational Program)
Answer:
6
Step-by-step explanation:
We know that the area of a circle is equal to 
.
A semi-circle is a half-circle, meaning that it will have half of the area of a full circle.
Therefore, a semi-circle's area is equivalent to 
.
Set this equation equal to 18.
Solve for r.
We then find that r = 6.
Now, we need to find the circumference. We know that the equation for the circumference of a circle is 2r. Since we only need the perimeter of half of a circle, our circumference equation will equal r.
Plug 6 in for r.
The perimeter of the garden is equal to 6.
Answer:
c. an observed difference is 0.12 and P < 0.0001
Step-by-step explanation:
Let p1 be the proportion of the students who received musical instruction received a passing grade
Let p2 be the proportion of the students who didn't receive musical instruction received a passing grade
Null and Alternative hypotheses are:
: p1-p2=0
: p1-p2≠0
Test statistic can be found using the equation:
where
- p1 is the sample proportion of the students who received musical instruction received a passing grade (
)
- p2 is the sample proportion of the students who didn't receive musical instruction received a passing grade (
)
- p is the pool proportion of p1 and p2 (
)
- n1 is the sample size of the students who received musical instruction (3239)
- n2 is the sample size of the students who didn't receive musical instruction (2787)
Thus, 
≈ 11.84 gives p-value < 0.0001
Observed difference is: 0.87-0.75=0.12
