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tatyana61 [14]
3 years ago
14

Find the perimeter of an isosceles triangle. The base is 3y and each side is (0.6y-7).

Mathematics
1 answer:
agasfer [191]3 years ago
6 0

Answer:

Perimeter = 4.2y - 14

Step-by-step explanation:

Perimeter of a triangle = the sum of the three sided of the triangle.

In an isosceles triangle, there are two equal sides and a base.

Perimeter = (0.6y - 7) + (0.6y - 7) + 3y

Perimeter = (0.6y + 0.6y + 3y) - 7 - 7

Perimeter = 1.2y + 3y - 14

Perimeter = 4.2y - 14

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Use Lagrange multipliers to find the maximum and minimum values of the function subject to the given constraint. (If an answer d
andrey2020 [161]

Answer:

The maximum value is 1/27 and the minimum value is 0.

Step-by-step explanation:

Note that the given function is equal to (xyz)^2 then it means that it is positive i.e f(x,y,z)\geq 0.

Consider the function F(x,y,z,\lambda)=x^2y^2z^2-\lambda (x^2+y^2+z^2-1)

We want that the gradient of this function  is equal to zero. That is (the calculations in between are omitted)

\frac{\partial F}{\partial x} = 2x(y^2z^2 - \lambda)=0

\frac{\partial F}{\partial y} = 2y(x^2z^2 - \lambda)=0

\frac{\partial F}{\partial z} = 2z(x^2y^2 - \lambda)=0

\frac{\partial F}{\partial \lambda} = (x^2+y^2+z^2-1)=0

Note that the last equation is our restriction. The restriction guarantees us that at least one of the variables is non-zero. We've got 3 options, either 1, 2 or none of them are zero.

If any of them is zero, we have that the value of the original function is 0. We just need to check that there exists a value for lambda.

Suppose that x is zero. Then, from the second and third equation we have that

-2y\lambda = -2z\lambda. If lambda is not zero, then y =z. But, since -2y\lambda=0 and lambda is not zero, this implies that x=y=z=0 which is not possible. This proofs that if one of the variables is 0, then lambda is zero. So, having one or two variables equal to zero are feasible solutions for the problem.

Suppose that only x is zero, then we have the solution set y^2+z^2=1.

If both x,y are zero, then we have the solution set z^2=1. We can find the different solution sets by choosing the variables that are set to zero.

NOw, suppose that none of the variables are zero.

From the first and second equation we have that

\lambda = y^2z^2 = x^2z^2 which implies x^2=y^2

Also, from the first and third equation we have that

\lambda = y^2z^2 = x^2y^2 which implies x^2=z^2

So, in this case, replacing this in the restriction we have 3z^2=1, which gives as another solution set. On this set, we have x^2=y^2=z^2=\frac{1}{3}. Over this solution set, we have that the value of our function is \frac{1}{3^3}= \frac{1}{27}

4 0
3 years ago
What is the solution to -(4x-3) = -7(9+x) ???
Likurg_2 [28]

Answer:

The solution is -22

Step-by-step explanation:

<em>The solution of an equation is the value of the variable of the equation</em>

∵ -(4x - 3) = -7(9 + x)

→ Simplify each side

∵ -(4x) - -(3) = -7(9) + -7(x)

∴ (-4x) - (-3) = -63 + (-7x)

→ Remember (-)(-) = (+) and (-)(+) = (-)

∴ -4x + 3 = -63 - 7x

→ Add 7x to both sides

∴ -4x + 7x + 3 = -63 - 7x + 7x

∴ 3x + 3 = -63

→ Subtract 3 from both sides

∵ 3x + 3 - 3 = -63 - 3

∴ 3x = -66

→ Divide both sides by 3

∴ x = -22

∴ The solution is -22

8 0
3 years ago
The height in meters of a toy rocket at t seconds can be found by the
OlgaM077 [116]

Answer:   81.2

Step-by-step explanation:

h(t) = -5t² + 40t + 1.2

h(4) = -5(4)² + 40(4) + 1.2                   We plug 4 seconds as t, and solve h(4)

h(4) = -80 + 160 + 1.2

h(4) = 80 + 1.2

h(4) = 81.2

4 0
3 years ago
A hot air balloon descends from an altitude of 2,000 feet at a constant rate of 90 feet per minute. The graph shows the altitude
SSSSS [86.1K]
Y=90x+2,000

90 is the rate of change because the hot air balloon descends 90 feet per minute.
And 2,000 is the starting point because the hot air balloon started the descent at 2,000 feet.
3 0
3 years ago
Smallest to largest 1.306 1.36 1.06 1.031
Readme [11.4K]
1.06, 1.031, 1.36, 1.306
7 0
4 years ago
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