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Lina20 [59]
3 years ago
6

Find the sum of 382 - 8 - 10 and 1042 +2 - 10.

Mathematics
1 answer:
mars1129 [50]3 years ago
8 0

Answer:

364 and 1034

Step-by-step explanation:

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Which graph represents the given equation?
Alchen [17]

9514 1404 393

Answer:

  A

Step-by-step explanation:

The axis of symmetry of quadratic ax²+bx+c is x=-b/(2a). For the given equation, the axis of symmetry is ...

  x = -4/(2(3/2)) = -4/3

The only graph with its vertex at x=-4/3 is graph A.

_____

<em>Additional comment</em>

You can also make the correct choice by evaluating the equation at a couple of different values of x. Convenient ones are x= -1, or 0, or +1. The value at x=0 is the y-intercept, (0, -2), which seems to be a point on all of the graphs. The value at x=1 is 3/2+4-2 = 3.5, which looks like it is only seen on graph A.

7 0
3 years ago
Simplify to create an equivalent expression. 8−4(−x+5) Choose 1 answer: A 4x−12 B −4x−12 C 4x+13 D 4x+5
Kaylis [27]

Answer:

A (4x-12)

Step-by-step explanation:

Still think of PEMDAS: 8-4(-x=5)

a) Multiply -4(-x + 5)

* -4(-x) = 4x (remember a neg x neg = pos)

* -4(5) = - 20

b) Now it reads = 8 +4x - 20

c) put all like terms together

* 8 - 20 = -12

6 0
3 years ago
The length of a rectangle is 3 inches more than twice its width, and its area is 65 square inches. What is the width?
tino4ka555 [31]

That makes no sense, what DO you get?

The correct answer is, A, or question 1, or 2w + 3.

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My profile name is SweetyPie12, why don't you hit that friend request button!:)

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lol ;)

7 0
3 years ago
2. f(x)=4x+1 and ​g(x)=x2−4x−5​, find ​(g◦​f)(4​).
Goryan [66]

Answer:

(g · f)(4) = 45

Step-by-step explanation:

f(x)=4x+1

g(x)=x² - 4x- 5

(g · f)(x) = 4(x² - 5) + 1

(g · f)(4) = 4(4² - 5) + 1

Following pemdas

(g · f)(4) = 4(16 - 5) + 1

(g · f)(4) = 4(11) + 1

(g · f)(4) = 44 + 1

(g · f)(4) = 45

8 0
2 years ago
Which inequality represents all values of x for which the quotient below is O A. 1 O B. XS -1 O c. x 1 O D. x -1
Olegator [25]
We have to solve two inequations:
Equation 1:
30(x-1)≥0
(x-1)≥0/30
(x-1)≥0
x≥1    (solution 1)

Equation 2:
5x²≥0
x≥0

The solution is: solution1 <span>∩ solution2

Teherefore; x≥1
</span>
6 0
3 years ago
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