First, let's multiply the first equation by two. This is because we have to eliminate either x or y by subtraction or addition so that means either both of the x's or both of the y's in the two equations have to be equal. Thus multiplying the first equation by 2 will give 12x+8y=4.
Next, subtract equation two from equation one:
We get a third equation, 2x-0= -28
Thus, x=-28/2. x= -14
In the same way, to find y, we need to eliminate the x's in both equations. This can be done by multiplying the first equation by 5 and the second by 3
Thus : 30x+20y=10 and 30x-24y=96
Subtracting the second equation from the first, we have 0+44y=-86
y=-86/44
y = 1.96 or 43/22
<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em>
<em>H</em><em>ope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>you</em><em>.</em><em>.</em><em>.</em>
<em>G</em><em>ood</em><em> </em><em>luck</em><em> </em><em>on</em><em> </em><em>your</em><em> </em><em>assignment</em>
<em>~</em><em>p</em><em>r</em><em>a</em><em>g</em><em>y</em><em>a</em>
The equation is true.
y^13/y^12 = y^8 * y^-9
y=y^8 * y^-9
y=y^-1
y=1/y
y-1/y=0
y
y^2 - 1 = 0
y = 1 , -1
The probability that a flight that departs on schedule also arrives on schedule
83%×68%=56%
Answer:
Step-by-step explanation:
+ 
( multiply by 3 and by 7 to get a common denominator)
+ 
=
