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2 years ago

Sole the inequality x-8>-4

Mathematics

1 answer:

joja [24]2 years ago

5 0

Answer:

$x>4$

Based on this, we know the correct number line will be an empty bubble with a line going to the right of 4.

Step-by-step explanation:

$x-8>-4$

add 8 to both sides of the inequality

$x>4$

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siniylev [52]

Answer: 1110 0111

Step-by-step explanation:

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2 years ago

How many solutions does x2 = 9 have?

MrRa [10]

It should have 2 solutions

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2 years ago

Read 2 more answers

Given f(x) =

sergejj [24]

Answer:

Step-by-step explanation:

We are given the function:

$\displaystyle f(x) = \left\{ \begin{array}{ll} 2\cos(\pi x) \text{ for } x \leq -1 \\ \\ \displaystyle \frac{2}{\cos(\pi x)}\text{ for } x > -1 \end{array} \right.$

And we want to find:

$\displaystyle \lim_{x\to -1}f(x)$

So, we need to determine whether or not the limit exists. In other words, we will find the two one-sided limits.

Left-Hand Limit:

$\displaystyle \lim_{x\to-1^-}f(x)$

Since we are approaching from the left, we will use the first equation:

$\displaystyle =\lim_{x\to -1^-}2\cos(\pi x)$

By direct substitution:

$=2\cos(\pi (-1))=2\cos(-\pi)=2(-1)=-2$

Right-Hand Limit:

$\displaystyle \lim_{x\to -1^+}f(x)$

Since we are approaching from the right, we will use the second equation:

$=\displaystyle \lim_{x\to -1^+}\frac{2}{\cos(\pi x)}$

Direct substitution:

$\displaystyle =\frac{2}{\cos(\pi (-1))}=\frac{2}{\cos(-\pi)}=\frac{2}{(-1)}=-2$

So, we can see that:

$\displaystyle \displaystyle \lim_{x\to-1^-}f(x)=\displaystyle \lim_{x\to -1^+}f(x) =-2$

Since both the left- and right-hand limits exist and equal the same thing, we can conclude that:

$\displaystyle \lim_{x \to -1}f(x)=-2$

Our answer is A.

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3 years ago

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mel-nik [20]

21 over 50 is

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The same thing, just put 21 on top, a line under it, and below that line, put the 50

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