The vertex of the graph of f(x)= |x-3|+6 is located at (3, 6)
<h3>How to determine the vertex?</h3>
The equation of the function is given as:
f(x) = |x - 3| + 6
The above function is an absolute value function.
An absolute value function is represented as:
f(x) = a|x - h| + k
Where:
Vertex = (h, k)
By comparison, we have:
Vertex = (3, 6)
Hence, the vertex of the graph of f(x)= |x-3|+6 is located at (3, 6)
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Answer:mot sire
Step-by-step explanation:
Good news: they are all like terms
9x + 5x -3x -8x = 3x
Answer:
⇒ The given quadratic equation is x2−kx+9=0, comparing it with ax2+bx+c=0
∴ We get, a=1b=−k,c=9
⇒ It is given that roots are real and distinct.
∴ b2−4ac>0
⇒ (−k)2−4(1)(9)>0
⇒ k2−36>0
⇒ k2>36
⇒ k>6 or k<−6
∴ We can see values of k given in question are correct.
