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3 years ago

A regular polygon has an exterior angle of 40

2 answers:

8 0

9
The exterior angles of any regular polygon must add up to 360. Since the angle measure given in the questions is 40, take 360/ 40= 9. Meaning there are 9 exterior angles and therefore 9 sides to the polygon.

Viefleur [7K]3 years ago

6 0

Answer:

9 sides

Step-by-step explanation:

The sum of the exterior angles of a polygon = 360°

To find the number of sides n divide the sum by 40°

n = 360° ÷ 40° = 9

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Robert has fish, chickens, and dogs. There are 28 eyes total and 16 legs total. Also, there are twice as many fish as chickens.

Elena L [17]

Answer : 2 dogs.
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4 years ago

Andre wrote the inequality to plan his time. Describe what 3x + 10 ≤ 30 represent in this inequality.

kumpel [21]

Answer: Andre can make 6 small cranes.

Step-by-step explanation:

3x + 10 is less than or equal to 30

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X is the amount of small cranes

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credits:

breannacaitlin6 solved it

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3 years ago

Read 2 more answers

Determine all real numbers a$ such that the inequality $ |x^2 2ax 3a|\le2$ has exactly one solution in x$.

vovikov84 [41]

Answer:

$x=-1, S=\{x\:\in\mathbb{R}:x=-1\}$

Step-by-step explanation:

For the sake of clarity, assuming you meant:

$|x^{2}+2x+3|\le2$

1) Absolute Value or Modulus functions has one property that assures us that:

$If |a|$

2) Solving for x

$I) x^{2}+2x+3\geqslant -2\Rightarrow x^{2}+2x+5\geqslant 0 \Rightarrow x\geqslant \frac{-2\pm \sqrt{2^{2}-4*1*5}}{2} x'\geqslant \frac{-2+4i }{2} \:and\:x''\geqslant \frac{-2-4i }{2}$

Not defined in Real Set of Numbers

Evaluating $x^{2}+2x+3\leqslant 2$ :

$x^{2}+2x+3\leqslant 2\\x^{2}+2x+1\leqslant 0\\(x+1)(x+1)\leqslant 0 \Rightarrow S=\{-1\}$

3) So, since for the first case the Discriminant Δ <0, then the solutions presented for $x^{2}+2x+3\geqslant -2\: \in \mathbb{C}$ . The only solution in the Real Set for the inequality $|x^{2}+2x+3|\le2$ is $S=\{-1\}$ , i.e. x=-1.

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