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svetoff [14.1K]
3 years ago
12

two ferries start moving toward each other from opposite riverbanks, a and b. when they pass each other for the first time, the

distance to riverbank b is 100 meters. each ferry starts its return trip as soon as it reaches its destination. when the ferries meet for the second time, the distance to riverbank A is 50 meters. what is the distance between riverbanks a and b? Help I will give 40 points
Mathematics
1 answer:
Usimov [2.4K]3 years ago
3 0

Let 'x' be the distance from THE far bank   where 700 is the distance to the NEAR bank

boat one has travelled 700    (rate = 700/unit time)         boat two has travelled   x    rate = x / unit time

boat one then travels   x  + 400  more      and boat two travels   700 + (700+x -400) more    when they meet

The time is the same      rate x time = distance      distance/rate = time     equate the distances divided by the respective rates

(700 + x + 400)/700     =    (  x  +  700     +  (700+x-400) )/x

1100x + x^2 = 1400x + 700000

x^2-300x -700000 = 0                         quadratic formula yields  x = 1000  

One boat travels 700   the other   1000 whe they first meet.....width of river =   700+ 1000 = 1700 m

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<h3>What is the expected value?</h3>

The expected value is the cost you would have to pay subtracted from the total value of one package.

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svlad2 [7]

Answer:

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Step-by-step explanation:

This is a simple interest problem.

The simple interest formula is given by:

E = P*I*t

In which E are the earnings, P is the principal(the initial amount of money), I is the interest rate(yearly, as a decimal) and t is the time.

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It will take 14.29 years for your bank balance to double from $1,000 to $2,000.

8 0
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