Answer:
The answer is the digit 3 is on the Ten-Thousandths place.
Step-by-step explanation:
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See the picture attached to better understand the problem
we know that
If two secant segments are drawn to a <span>circle </span><span>from an exterior point, then the product of the measures of one secant segment and its external secant segment is equal to the product of the measures of the other secant segment and its external secant segment.
</span>so
jl*jk=jn*jm------> jn=jl*jk/jm
we have
<span>jk=8,lk=4 and jm=6
</span>jl=8+4----> 12
jn=jl*jk/jm-----> jn=12*8/6----> jn=16
the answer is
jn=16
we know that
If two secant segments are drawn to a <span>circle </span><span>from an exterior point, then the product of the measures of one secant segment and its external secant segment is equal to the product of the measures of the other secant segment and its external secant segment.
</span>so
jl*jk=jn*jm------> jn=jl*jk/jm
we have
<span>jk=8,lk=4 and jm=6
</span>jl=8+4----> 12
jn=jl*jk/jm-----> jn=12*8/6----> jn=16
the answer is
jn=16
Perimeter of a shape is the total length of its border
Figure 1, perimeter = 5 units
Figure 2, perimeter = 7 units
Figure 3, perimeter = 9 units
Figure 4, perimeter = 11 units
Notice that the perimeter is forming an Arithmetic sequence; 5, 7, 9, 11 with a common difference of 2
The general form of an Arithmetic sequence is
Where 'd' is a common difference and 'n' is the number of terms.
We have d = 2, and
zero term = the term before the first term = 3
⇒ This is the rule to find the perimeter of the next figures
Figure 1, perimeter = 5 units
Figure 2, perimeter = 7 units
Figure 3, perimeter = 9 units
Figure 4, perimeter = 11 units
Notice that the perimeter is forming an Arithmetic sequence; 5, 7, 9, 11 with a common difference of 2
The general form of an Arithmetic sequence is
Where 'd' is a common difference and 'n' is the number of terms.
We have d = 2, and
zero term = the term before the first term = 3