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Anestetic [448]
3 years ago
13

14/15 + 8/15 + 4/5 please help

Mathematics
2 answers:
trapecia [35]3 years ago
5 0

Answer:

=\frac{34}{15}

=2\frac{4}{15}

Step-by-step explanation:

With unlike denominators find the Least Common Denominator (LCD)

LCD = 15

Multiplying numerators and denominators to get the LCD in all fraction denominators

=\frac{14}{15} +\frac{8}{15} +\frac{4*3}{5*3}

With like denominators we can operate on just the numerators

=\frac{14+8+12}{15}

=\frac{34}{15}

Simplifying the answer

=\frac{34}{15} \\=2\frac{4}{15}

Annette [7]3 years ago
3 0

Answer:

2.267

Step-by-step explanation:

Step 1 of 3: Add.

Add

Highlighted:14 over 15

14

15

Highlighted:+ Highlighted:8 over 15

8

15

+ 4 over 5

4

5

= Highlighted:22 over 15

22

15

+ 4 over 5

4

5

Step 1 of 3: Add, sub-step a: Add.

Add

14 over 15

14

15

+ 8 over 15

8

15

= ( 14 + 8 ) over 15

14 + 8

15

= 22 over 15

22

15

Step 1 of 3: Add.Hide

Step 2 of 3: Add.

Add

22 over 15

22

15

+ 4 over 5

4

5

= 34 over 15

34

15

Step 2 of 3: Add, sub-step a: Find common denominator.

Find common denominator

22 over 15

22

15

+ 4 over 5

4

5

= ( 22 × 1 ) over ( 15 × 1 )

22 × 1

15 × 1

+ ( 4 × 3 ) over ( 5 × 3 )

4 × 3

5 × 3

= 22 over 15

22

15

+ 12 over 15

12

15

15 is the least common multiple of denominators 15 and 5. Use it to convert to equivalent fractions with this common denominator.

Step 2 of 3: Add, sub-step b: Add.

Add

22 over 15

22

15

+ 12 over 15

12

15

= ( 22 + 12 ) over 15

22 + 12

15

= 34 over 15

34

15

Step 2 of 3: Add.Hide

Step 3 of 3: Simplify.

Simplify

34 over 15

34

15

= 2 and 4 over 152

4

15

Step 3 of 3: Simplify, sub-step a: Reduce fraction to lowest terms.

Reduce fraction to lowest terms

1 is the greatest common divisor of 34 and 15. The result can't be further reduced.

Step 3 of 3: Simplify, sub-step b: Convert improper fraction to mixed number.

Convert improper fraction to mixed number

34 over 15

34

15

= 2 and 4 over 152

4

15

34 ÷ 15 = 2 remainder 4

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<h3>How to determine ordered pair?</h3>

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