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Kisachek [45]
3 years ago
5

7.90×10^−2/1.0×10^−5

Mathematics
1 answer:
Nitella [24]3 years ago
4 0

Answer:

\frac{7.90 \times  {10}^{ - 2} }{1.0 \times  {10}^{ - 5} }  \\  = 7.9 \times  {10}^{5 - 2}  \\ = 7.9 \times  {10}^{3}

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What are the roots of 3x2 + 10 = 4x?
sveticcg [70]

Answer:

Option C is correct.

roots of the given equation , x =\frac{2\pm i\sqrt{26}}{3}

Step-by-step explanation:

Given the equation: 3x^2+10 = 4x

We can write this equation as:

3x^2-4x + 10 =0

A quadratic equation is in the form of ax^2+bx+c =0      ......[1] where a,b ,c are the coefficient and x is the variable,

the solution of the equation is given by;

x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}

On comparing given equation with equation [1] we get;

a = 3 , b = -4 and c =10

So, the solution of the given equation is given by;

x = \frac{-(-4)\pm\sqrt{(-4)^2-4(3)(10)}}{2(3)}

or

x =  \frac{4\pm\sqrt{(16-120}}{6} = \frac{4\pm\sqrt{(-104)}}{6} = \frac{4\pm\sqrt{(-4 \times 26)}}{6}

or

x =\frac{4\pm2 \sqrt{(-26)}}{6} = \frac{4\pm2 i\sqrt{26}}{6}    [∴\sqrt{-1} = i

Simplify:

x =\frac{2\pm i\sqrt{26}}{3}

therefore, the roots of the given equation are; x =\frac{2\pm i\sqrt{26}}{3}

5 0
3 years ago
Read 2 more answers
A motorboat travels 168 kilometers in 4 hours going upstream. It travels 280 kilometers going downstream in the same amount of t
Grace [21]

Answer:

The speed of the boat is 56 km/hr

The rate of the current is 14 km/hr

Step-by-step explanation:

We are given the following;

  • Distance traveled upstream = 168 km
  • Time taken to travel upstream = 4 hours
  • Distance traveled down stream = 280 km
  • Time taken down stream = 4 hours

We are required to determine the speed of the boat in still water and the speed of the current.

We are going to take;

Speed of the boat as = x km/hr

Rate of flow of current = y km/hr

We can determine the speed of the boat upstream;

Speed = Distance ÷ time

               = 168 km ÷ 4 hours

               = 42 km/hr

But, the speed upstream is given by (x - y) km/hr

Therefore; ( x-y) km/hr = 42 km/hr ......................... Eqn 1

Speed of the boat down stream

    speed = 280 km ÷ 4 hours

                = 70 km/hr

But, the speed downstream is given by (x+y) km/hr

Therefore, x+y km/hr = 70 km/hr ........................... Eqn 2

Solving Eqn 1 and Eqn 2 simultaneously;

x - y = 42

x + y = 70

Eliminating x

-2y = - 28

    y = 14 km/hr

Solving for x,

x = 42 + y

   = 42 + 14

   = 56 km/hr

Therefore, the speed of the boat is 56 km/hr while the rate of the current is 14 km/hr

8 0
4 years ago
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