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lakkis [162]
3 years ago
10

How do I solve this man!!

Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
6 0

Answer:

Step-by-step explanation:

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x= 34°

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Because segments AB and BC are congruent, their corresponding angles (<BAD and <BCD) would also be congruent to each other, meaning that both would be 56°.

Knowing that triangles add up to 180°, the whole triangle (ABC) would then have 2 angles that are 56° and the top angle (<ABC) would be 68°

Splitting those in half ( because <ABD and <CBD are congruent), each would be 34° (thus x=34°)

Looking now at the two separate triangles (ABD and CBD), we can determine that both <BDA and <BDC are 90° (right angles) because 180-34-56=90°.

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In the picture with the triangles Phillip is correct because  the triangle does not give the measurements of the same side so there is no proof of any sides to be the same. With the other picture what I did was I reversed the translation which got the points A (-2,1) B (-5,3) Then I reversed the rotation which got me A(2,-1) and B (5,-3). So line AB endpoints would be located A (2,-1) and B (5,-3).

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An archer shoots an arrow up towards a target located on a hill, which is shown by the graph. Which set of equations best models
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The set of equations best models the point of intersection of the arrow and the target is:

y = –0.008x² + 0.2x + 7 and y = 0.12x.

<h3>What are the equations of the point of intersection?</h3>

To find the equations, we have to look at two things.

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The coordinates of the point are (35, 4.2), hence the best linear representation is:

y = 0.12x.

This leaves the first two options. The trajectory is concave down, which removes the second option, hence the correct option is:

y = –0.008x² + 0.2x + 7 and y = 0.12x.

A similar problem, involving a point of intersection, is given at brainly.com/question/11337174

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