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brilliants [131]
2 years ago
8

After spraying perfume on her neck, Tasha becomes less aware of the scent over time. What property is this describing

Mathematics
1 answer:
Yuri [45]2 years ago
7 0

Answer:

Sensory adaptation? im guessing

Step-by-step explanation:

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The table shows the results of a survey on people’s favorite fruit. What percent of the people chose strawberry as their favorit
Sphinxa [80]

<u><em>Answer:</em></u>

24.2%

<u><em>Explanation:</em></u>

<u>The percentage of people choosing strawberry can be calculated as follows:</u>

Percentage = \frac{PeopleChoosingStrawberry}{TotalNumberOfSurveyedPeople} * 100

<u>We have:</u>

Number of people choosing strawberry = 15 people

Total number of surveyed people = 17 + 10 + 17 + 3 + 15 = 62 people

<u>Substitute in the above rule to get the percentage as follows:</u>

Percentage = \frac{15}{62}*100 = 24.19 = 24.2%

Hope this helps :)

3 0
3 years ago
Guys im giving max points for this, please give me a correct answer and best gets brainliest.
lukranit [14]

Answer:

y=-2/3 x +4

Step-by-step explanation:

slop = (6-0)/(-3-6)= -2/3

c= 4  (when x =0)

line equation:

y= mx + c

y=-2/3 x +4

4 0
3 years ago
Read 2 more answers
Plzz help asap.......​
SSSSS [86.1K]

Answer:

29.78 feet

Step-by-step explanation:

4 0
3 years ago
A hobby store prices model train track using a proportional relationship between the length of track (in inches) and the cost in
Andrei [34K]

Answer:

2.5

Step-by-step explanation:

The constant of probability is 16/6.4=2.5

3 0
3 years ago
Read 2 more answers
Integrate this two questions ​
tankabanditka [31]

Simplify the integrands by polynomial division.

\dfrac{t^2}{1 - 3t} = -\dfrac19 \left(3t + 1 - \dfrac1{1 - 3t}\right)

\dfrac t{1 + 4t} = \dfrac14 \left(1 - \dfrac1{1 + 4t}\right)

Now computing the integrals is trivial.

5.

\displaystyle \int \frac{t^2}{1 - 3t} \, dt = -\frac19 \int \left(3t + 1 - \frac1{1-3t}\right) \, dt \\\\ = -\frac19 \left(\frac32 t^2 + t + \frac13 \ln|1 - 3t|\right) + C \\\\ = \boxed{-\frac{t^2}6 - \frac t9 - \frac{\ln|1-3t|}{27} + C}

where we use the power rule,

\displaystyle \int x^n \, dx = \frac{x^{n+1}}{n+1} + C ~~~~ (n\neq-1)

and a substitution to integrate the last term,

\displaystyle \int \frac{dt}{1-3t} = -\frac13 \int \frac{du}u \\\\ = -\frac13 \ln|u| + C \\\\ = -\frac13 \ln|1-3t| + C ~~~ (u=1-3t \text{ and } du = -3\,dt)

8.

\displaystyle \int \frac t{1+4t} \, dt = \frac14 \int \left(1 - \frac1{1+4t}\right) \, dt \\\\ = \frac14 \left(t - \frac14 \ln|1 + 4t|\right) + C \\\\ = \boxed{\frac t4 - \frac{\ln|1+4t|}{16} + C}

using the same approach as above.

5 0
2 years ago
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