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2 years ago

14

The graph of a polynomial function has zeroes 0 (multiplicity 2) , 1 (multiplicity 2), and 5/2 (multiplicity 2). Write a functio

n in standard form that could represent this function

1 answer:

pogonyaev2 years ago

6 0

Answer:

x^6 - 7x^5 + 69/4x^4 + -35/2x^3 + 25/4x^2

Step-by-step explanation:

x^2(x-1)^2(x-5/2)^2 is the factored form of the polynomial. Now you simplify it to convert to standard form.

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The plot below shows the ages of residents at Oak Creek Assisted Living. The black dots represent residents in the east wing, an

KATRIN_1 [288]

Answer:

There isn't a plot

Step-by-step explanation:

8 0

3 years ago

Factories A, B and C produce computers. Factory A produces 4 times as manycomputers as factory C, and factory B produces 7 times

Elina [12.6K]

Answer:

The probability is $P(A') = 0.485$

Step-by-step explanation:

Let assume that the number of computer produced by factory C is k = 1

So From the question we are told that

The number produced by factory A is 4k = 4

The number produced by factory B is 7k = 7

The probability of defective computers from A is $P(A) = 0.04$

The probability of defective computers from B is $P(B) = 0.02$

The probability of defective computers from C is $P(C) = 0.03$

Now the probability of factory A producing a defective computer out of the 4 computers produced is

$P(a) = 4 * P(A)$

substituting values

$P(a) = 4 * 0.04$

$P(a) = 0.16$

The probability of factory B producing a defective computer out of the 7 computers produced is

$P(b) = 7 * P(B)$

substituting values

$P(b) = 7 * 0.02$

$P(b) = 0.14$

The probability of factory C producing a defective computer out of the 1 computer produced is

$P(c) = 1 * P(C)$

substituting values

$P(c) = 1 * 0.03$

$P(b) = 0.03$

So the probability that the a computer produced from the three factory will be defective is

$P(t) = P(a) + P(b) + P(c)$

substituting values

$P(t) = 0.16 + 0.14 + 0.03$

$P(t) = 0.33$

Now the probability that the defective computer is produced from factory A is

$P(A') = \frac{P(a)}{P(t)}$

$P(A') = \frac{ 0.16}{0.33}$

$P(A') = 0.485$

3 0

3 years ago

URGENT NEED BEFORE 5:00<br>8.6 x 2.9

dedylja [7]

Just use a calculator.
but if this is not a joke
the answer is 24.94

3 0

3 years ago

Mr. Moss had 2 gallons of paint. He painted 3 doors. How many benches can he paint with the paint that is left? Show your work.

RUDIKE [14]

Answer:

uh depends on how much paint he used for the doors and how much paint he needs for the benches

Step-by-step explanation:

8 0

3 years ago

The focus of a parabola is (0, -3) and the directrix is y = 3. What is the equation of the parabola?

mart [117]

Focus has coordinates (0, a)
a = -3
Thus, 4a = 4(-3) = -12

Because a is negative, we know it will be a concave down or concave left parabola. Hence, A and D can be eliminated. And we know it has to be B because the directrix is the horizontal line y = 3. Hence, the equation of the parabola becomes:

$x^{2} = -12y$ or $y = -\frac{1}{12}x^{2}$

5 0

3 years ago