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vfiekz [6]
3 years ago
13

A high school teacher teaches three classes per day. Her first class has double the number of students as her

Mathematics
1 answer:
Aneli [31]3 years ago
3 0

Answer: 15 students in her second class.

Step-by-step explanation:

Let A, B, and C stand for the number of students in each class. See the attached table.

The column labelled "Students" is formed by assinging B to the second class and finding how the other two classes relate to B. Class A has twice as many students as class B, so A = 2B. Class C has 5 more students than B, so C = B+5.

The total students amount to 65, whcih is the sum of A, B, and C:

A + B + C = 65

Substitute the values of A and C into this equation:

A + B + C = 65

2B + B + (B+5) = 65

4B + 5 = 65

4B = 60

B = 16

Use B=16 and solve for the other two classes (dotted blue line).

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blsea [12.9K]

Answer:

  • a) 2/3p
  • b) q + 1/2p

Step-by-step explanation:

<u>Given</u>

  • AB  = p
  • AD = q

a)

  • DC /AB = 3/2 ⇒
  • DC = 3/2AB = 3/2p

b)

  • BC = AD + (DC - AB)
  • BC = q + (3/2p - p) = q + 1/2p
8 0
3 years ago
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I will Mark you brainliest if you explain your work
Vlad1618 [11]

Answer:

(-1/2, 1)

Step-by-step explanation:

I just used the midpoint formula, and plugged in the points. I hope this helps!

=(x^2+x^1 /2 , y^2+y^1 /2)

=(-2+1 /2 , -5+3 /2)

=(-1/2, 1)

8 0
3 years ago
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kykrilka [37]

Answer:

1.false

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3.false

7 0
3 years ago
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I NEED HELP ASAP!!
zzz [600]

Answer:

C. {-5,-4, -3, 1, 2, 5}

Step by step explanation:

We have been given a graph and we are asked to find the domain of the relation represented in graph.

We can see that our graph is a series of unconnected points. Our function represents integer values. So we can see that our graph represents a discrete function.    

Since we know that domain of a discrete function is set of inputs values consisting of only certain values in an interval. .

The set of first value from each of the given points would made domain of our function. Upon looking at our graph we can see that domain of our function is -5,-4, -3, 1, 2 and 5.  

Therefore, option C is the correct choice.


7 0
3 years ago
Solving the linear equations variable on one side
Brums [2.3K]

The pick up fee is $2.50.

After each mile, $1.95 is added.

That is, after the first mile, we have;

\begin{gathered} \text{Fe}e=\text{ 2.50 + 1.95(1)} \\ \text{After the second mile, we have;} \\ Fee=\text{ 2.50+1.95(2)} \end{gathered}

Isaac total charge = $27.46;

Generally, let the number of miles driven by the taxi be x, then we have;

1.95x+2.50=27.46

Solving for the number of miles Isaac travelled, we have;

\begin{gathered} 1.95x=27.46-2.50 \\ 1.95x=24.96 \\ x=\frac{24.96}{1.95} \\ x=12.8\text{miles} \end{gathered}

CORRECT OPTION:

1.95x+2.50=27.46;\text{ Isaac traveled 12.8 miles.}

4 0
2 years ago
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