A high school teacher teaches three classes per day. Her first class has double the number of students as her
1 answer:
Answer: 15 students in her second class.
Step-by-step explanation:
Let A, B, and C stand for the number of students in each class. See the attached table.
The column labelled "Students" is formed by assinging B to the second class and finding how the other two classes relate to B. Class A has twice as many students as class B, so A = 2B. Class C has 5 more students than B, so C = B+5.
The total students amount to 65, whcih is the sum of A, B, and C:
A + B + C = 65
Substitute the values of A and C into this equation:
A + B + C = 65
2B + B + (B+5) = 65
4B + 5 = 65
4B = 60
B = 16
Use B=16 and solve for the other two classes (dotted blue line).
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x is 7.5 hours
Step-by-step explanation:
Ben, Tim, and Sam have to do a certain job
- Ben can finish the job in 5 hours
- Tim can finish the job in 6 hours
- Sam can finish the job in x hours
- The three of them can finish the job in 2 hours if they work together
We need to find x
∵ Ben can finish the job in 5 hours
∴ The rate of Ben =
∵ Tim can finish the job in 6 hours
∴ The rate of Tim =
∵ Sam can finish the job in x hours
∴ The rate of Sam =
They will working together to finish the job in two hours, that means the sum of their rate is equal to 1/2
∵ They can finish the job in 2 hours if they work together
∴
To add the fractions find the LCM for all denominators to make all fractions with same denominators
∵ The LCM of 5, 6 ans x is (5 × 6 × x) = 30 x,
- Divide it by each denominator to find the new numerators
∵ 30 x ÷ 5 = 6 x , 30 x ÷ 6 = 5 x , 30 x ÷ x = 30
- Change all the denominators to 30 x and then write the new
numerators of each fraction
∴
Add the numerators and put the sum over 30 x
∵
- By using cross multiplication
∴ 2(11 x + 30) = 1(30 x)
- Simplify the both sides
∴ 22 x + 60 = 30 x
- Subtract 22 x from both sides
∴ 60 = 8 x
- Divide both sides by 8
∴ 7.5 = x
∴ The value of x is 7.5 hours
x is 7.5 hours
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