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2 years ago

M*(x+y)+4y/(x^2-xy-y^2)=(x+2y)/(x^2-xy-Y^2),find the value of M

Mathematics

1 answer:

dybincka [34]2 years ago

3 0

Answer: M = $\frac{x-2y}{x+y}$

Step-by-step explanation:

$\frac{M(x+y)+4y}{x^{2}-xy-y^{2} } =\frac{(x+2y)}{x^{2} -xy-y^{2} }$

M (x + y) + 4y = x + 2y (Multiply $x^{2} - xy-y^{2}$ in both sides)

M (x + y) = x + 2y - 4y

M (x + y) = x - 2y (Divide (x+y) from both sides)

M = $\frac{x-2y}{x+y}$

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The correct answers are the following:

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C) Decrease by $100

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B) 1,213=12n-275 - Plug in the value for P ($1,213).

1,488=12n - Add $275 to both sides.

124=n - Divide both sides by $12.

n=124  - This the number (n) of people that attended.

C) P=12n-375 - Change the value for expense to $375.

P=12(124)-375 - Plug in the value for n (124).

P=1488-375 - Simplify and find the difference.

P=1,113 - This is your profit.

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