Question

M*(x+y)+4y/(x^2-xy-y^2)=(x+2y)/(x^2-xy-Y^2),find the value of M

Answer 1

Answer: M  = $\frac{x-2y}{x+y}$  

Step-by-step explanation:

$\frac{M(x+y)+4y}{x^{2}-xy-y^{2} } =\frac{(x+2y)}{x^{2} -xy-y^{2} }$

M (x + y) + 4y = x + 2y (Multiply $x^{2} - xy-y^{2}$ in both sides)

M (x + y)  = x + 2y - 4y

M (x + y)  = x - 2y  (Divide (x+y) from both sides)

M  = $\frac{x-2y}{x+y}$