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inna [77]
2 years ago
14

Write 63 as the product of prime factors HOW AM I WRONG???

Mathematics
2 answers:
Verdich [7]2 years ago
6 0

Answer:

3x3x7

Step-by-step explanation:

Dw worry ur not wrong but mathswatch sometimes doesnt want you to simplify it and want you to write it all out :P

Hope this helps! :)

guajiro [1.7K]2 years ago
4 0

Answer:

Since, the prime factors of 63 are 3, 7. Therefore, the product of prime factors = 3 × 7 = 21.

Step-by-step explanation:

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OlgaM077 [116]

Answer:

Sam is incorrect

Step-by-step explanation:

We can calculate the lengths of the diagonals using Pythagoras' identity.

The diagonals divide the rectangle and square into 2 right triangles.

Consider Δ SRQ from the rectangle

SQ² = SR² + RQ² = 12² + 6² = 144 + 36 = 180 ( take square root of both sides )

SQ = \sqrt{180} ≈ 13.4 in ( to 1 dec. place )

Consider Δ ONM from the square

OM² = ON² + NM² = 6² + 6² = 36 + 36 = 72 ( take square root of both sides )

OM = \sqrt{72} ≈ 8.5 in ( to 1 dec. place )

Now 2 × OM = 2 × 8.5 = 17 ≠ 13.4

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3 years ago
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Nadusha1986 [10]

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Step-by-step explanation:

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3 years ago
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Assoli18 [71]
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Vaselesa [24]

Answer:

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Step-by-step explanation:

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3 years ago
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Answer:

(4√d)³

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