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Mamont248 [21]
3 years ago
11

A curve has the equation y = x^3 – 3x + 2

Mathematics
1 answer:
vladimir2022 [97]3 years ago
5 0

Answer:

PLEASE MARK ME BRAINLIEST!!!

Step-by-step explanation:

moddedcraftxdepic

02/28/2021

Mathematics

High School

answered

Y= x^3 + 8x^2 +5x

work out the coordinates of the two turning points 1  

You might be interested in
Calculus piecewise function. ​
Kipish [7]

Part A

The notation \lim_{x \to 2^{+}}f(x) means that we're approaching x = 2 from the right hand side (aka positive side). This is known as a right hand limit.

So we could start at say x = 2.5 and get closer to 2 by getting to x = 2.4 then to x = 2.3 then 2.2, 2.1, 2.01, 2.001, etc

We don't actually arrive at x = 2 itself. We simply move closer and closer.

Since we're on the positive or right hand side of 2, this means we go with the rule involving x > 2

Therefore f(x) = (x/2) + 1

Plug in x = 2 to find that...

f(x) = (x/2) + 1

f(2) = (2/2) + 1

f(2) = 2

This shows \lim_{x \to 2^{+}}f(x) = 2

Then for the left hand limit \lim_{x \to 2^{-}}f(x), we'll involve x < 2 and we go for the first piece. So,

f(x) = 3-x

f(2) = 3-2

f(2) = 1

Therefore, \lim_{x \to 2^{-}}f(x) = 1

===============================================================

Part B

Because \lim_{x \to 2^{+}}f(x) \ne \lim_{x \to 2^{-}}f(x) this means that the limit \lim_{x \to 2}f(x) does not exist.

If you are a visual learner, check out the graph below of the piecewise function. Notice the gap or disconnect at x = 2. This can be thought of as two roads that are disconnected. There's no way for a car to go from one road to the other. Because of this disconnect, the limit doesn't exist at x = 2.

===============================================================

Part C

You'll follow the same type of steps shown in part A.

However, keep in mind that x = 4 is above x = 2, so we'll deal with x > 2 only.

So you'd only involve the second piece f(x) = (x/2) + 1

You should find that f(4) = 3, and that both left and right hand limits equal this value. The left and right hand limits approach the same y value. The limit does exist here. There are no gaps to worry about when x = 4.

===============================================================

Part D

As mentioned earlier, since \lim_{x \to 4^{+}}f(x) = \lim_{x \to 4^{-}}f(x) = 3, this means the limit \lim_{x \to 4}f(x) does exist and it's equal to 3.

As x gets closer and closer to 4, the y values are approaching 3. This applies to both directions.

4 0
2 years ago
Whats times what equals negative 48 and adds up to negative 2
Georgia [21]
6 × -8 = -48

6 + -8 = -2
6 0
4 years ago
Pls can someone help me factorise: 4u²‐u-3
Murrr4er [49]

Answer:

(u - 1)(4u + 3)

Step-by-step explanation:

Given

4u² - u - 3

Consider the factors of the product of the coefficient of the u² term and the constant term which sum to give the coefficient of the u- term.

product = 4 × - 3 = - 12 and sum = - 1

The factors are -  4 and + 3

Use these factors to split the u- term

4u² - 4u + 3u - 3 ( factor the first/second and third/fourth terms )

= 4u(u - 1) + 3(u - 1) ← factor out (u - 1) from each term

= (u - 1)(4u + 3)

Thus

4u² - u - 3 = (u - 1)(4u + 3) ← in factored form

5 0
3 years ago
$39.60 sweater; 33% discount; 4.5% tax
Aleksandr [31]

Answer:

$39.06 - 13.07 = $25.99. $25.99 + 1.15 = $27.15

Step-by-step explanation:

6 0
3 years ago
SOS *Algebra one*
user100 [1]
This can be done in two ways
One method is to check the answer options in both f(x) and g(x) and select the one that matches for both.
The second is to form a quadratic equation and solving as such:
f(x) = g(x)
-x² + 4x + 12 = x + 8
x² - 3x - 4 = 0
(x - 4)(x + 1) = 0
x = 4; x = -1
Only x = 4 is given in the options, so the answer is B




3 0
3 years ago
Read 2 more answers
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