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2 years ago

❤️WILL REPORT BOTS❤️

Mathematics

2 answers:

11111nata11111 [884]2 years ago

8 0

Reflecting across the y axis

faltersainse [42]2 years ago

3 0

Answer:

The answer is reflection on the y-axis

Step-by-step explanation:

Reflection on the x-axis will change the y-intercept

Horizontal shrink will change the slope but not to the point of making the 3 negative

Horizontal stretch is the same concept

Thus Reflection on the y-axis on the y-axisis the answer

Hope this helps!

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Help PLEASE LIKE ACC STEP BY STEP FIND X PLZ

nikklg [1K]

Answer:

Step-by-step explanation:

The sum of interior angles in a rectangle is 360°

98 + 98 + 98 + 2x = 360

294 + 2x = 360

2x = 66°

x = 33

8 0

3 years ago

How is this solved using trig identities (sum/difference)?

GenaCL600 [577]

FIRST PART
We need to find sin α, cos α, and cos β, tan β
α and β is located on third quadrant, sin α, cos α, and sin β, cos β are negative

Determine ratio of ∠α
Use the help of right triangle figure to find the ratio
tan α = 5/12
side in front of the angle/ side adjacent to the angle = 5/12
Draw the figure, see image attached

Using pythagorean theorem, we find the length of the hypotenuse is 13
sin α = side in front of the angle / hypotenuse
sin α = -12/13

cos α = side adjacent to the angle / hypotenuse
cos α = -5/13

Determine ratio of ∠β
sin β = -1/2
sin β = sin 210° (third quadrant)
β = 210°

$cos \beta = -\frac{1}{2} \sqrt{3}$

$tan \beta= \frac{1}{3} \sqrt{3}$

SECOND PART
Solve the questions
Find sin (α + β)
sin (α + β) = sin α cos β + cos α sin β
$sin( \alpha + \beta )=(- \frac{12}{13} )( -\frac{1}{2} \sqrt{3})+( -\frac{5}{13} )( -\frac{1}{2} )$
$sin( \alpha + \beta )=(\frac{12}{26}\sqrt{3})+( \frac{5}{26} )$
$sin( \alpha + \beta )=(\frac{5+12\sqrt{3}}{26})$

Find cos (α - β)
cos (α - β) = cos α cos β + sin α sin β
$cos( \alpha + \beta )=(- \frac{5}{13} )( -\frac{1}{2} \sqrt{3})+( -\frac{12}{13} )( -\frac{1}{2} )$
$cos( \alpha + \beta )=(\frac{5}{26} \sqrt{3})+( \frac{12}{26} )$
$cos( \alpha + \beta )=(\frac{5\sqrt{3}+12}{26} )$

Find tan (α - β)
$tan( \alpha - \beta )= \frac{ tan \alpha-tan \beta }{1+tan \alpha tan \beta }$
$tan( \alpha - \beta )= \frac{ \frac{5}{12} - \frac{1}{2} \sqrt{3} }{1+(\frac{5}{12}) ( \frac{1}{2} \sqrt{3})}$

Simplify the denominator
$tan( \alpha - \beta )= \frac{ \frac{5}{12} - \frac{1}{2} \sqrt{3} }{1+(\frac{5\sqrt{3}}{24})}$
$tan( \alpha - \beta )= \frac{ \frac{5}{12} - \frac{1}{2} \sqrt{3} }{ \frac{24+5\sqrt{3}}{24} }$

Simplify the numerator
$tan( \alpha - \beta )= \frac{ \frac{5}{12} - \frac{6}{12} \sqrt{3} }{ \frac{24+5\sqrt{3}}{24} }$
$tan( \alpha - \beta )= \frac{ \frac{5-6\sqrt{3}}{12} }{ \frac{24+5\sqrt{3}}{24} }$

Simplify the fraction
$tan( \alpha - \beta )= (\frac{5-6\sqrt{3}}{12} })({ \frac{24}{24+5\sqrt{3}})$
$tan( \alpha - \beta )= \frac{10-12\sqrt{3} }{ 24+5\sqrt{3}}$

7 0

3 years ago

Which ordered pair is a solution of the equation?<br> 7x-2y=-57x−2y=−5

Yuri [45]

Answer:

what ordered pairs?

Step-by-step explanation:

6 0

2 years ago

24÷2²(-3)-7-2²-2(3-6) step by step please and thank you!

gavmur [86]

Answer:

$- 23$

Step-by-step explanation:

$24 \div {2}^{2} ( - 3) - 7 - {2}^{2} - 2(3 - 6) \\ 24 \div {2}^{2} ( - 3) - 7 - {2}^{2} - 2( - 3) \\ 24 \div 4( - 3) - 7 - 4 - 2( - 3)\\ 6(-3) - 7 - 4 -2(- 3) \\ - 18 - 7 - 4 + 6 \\ -25 -4 +6 \\ -29 +6 \\ - 23$

8 0

3 years ago

Read 2 more answers

What is the distance from (−2, 4) to (0, −6)? Round your answer to the nearest hundredth. 9.23 10.20 10.98 11.34

nevsk [136]

D = \/(0-(-2))² + (-6-4)²
d = \/(0+2)² + (-10)²
d = \/(2² + 100)
d = \/(4+100)
d = \/104
d ~ 10,20

5 0

3 years ago

Read 2 more answers